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Elena L [17]
3 years ago
6

Which statements describe properties of stars?

Physics
2 answers:
Ede4ka [16]3 years ago
7 0

Statements 1, 3, and 5 are true.

(A, C, and E)

Vanyuwa [196]3 years ago
7 0

Answer:

Statements 1,3, and 5 are correct

Explanation:

The facts which are correct of stars are ( among the given options)

1. Stars produce energy by nuclear fusion reaction.( in nuclear fusion reaction two molecules of hydrogen combine to form helium atom releasing a lot of energy.)

3. Stars are massive objects Composed of gases.

5. Stars are composed primarily of hydrogen and helium.

You might be interested in
Excited hydrogen atoms radiate energy in the _________
sveticcg [70]

Answer:

infrared, visible and ultraviolet regions.

Explanation:

7 0
3 years ago
Will pushing on a car always change the car's mechanical energy?
tamaranim1 [39]

I assume you mean that the car's motor is not running ... the car is just
sitting there.

If that's so, then the car's mechanical energy is just like the mechanical
energy of any other object.  It has potential energy if it's in a high place
from which it can roll or fall, and it has kinetic energy if it's moving.

-- If you make the car move by pushing it, then you gave it kinetic energy
that it didn't have while it was just sitting there.

-- If it's already moving slowly, and you're able to make it move faster by
pushing, then you increased its kinetic energy.

-- If you're able to push it up a hill, no matter how small the hill is but just
to any higher place, then you gave it more gravitational potential energy
than it had before you came along.

In all of these cases, if you exert a force and keep exerting it through some
distance while the car moves, then you have done "work", which is just
another name for mechanical energy, and your work adds to the mechanical
energy of the car.

But if you didn't move the car, then no matter how hard you pushed, no work
was done, and the car's mechanical energy didn't change.


7 0
3 years ago
How much heat is required to convert 0.3 kg of ice at 0°C to water at the same temperature
madreJ [45]

Answer:  

100,800 Jkg


The heat that is used to change the state of a mater is called latent heat.

In this case it is converting ice to water and it is called latent heat of fusion.

It is given by:

Heat  = mc

where m is the mass of ice and l is the specific latent heat of fusion of ice.

l = 0.336 MJ

Heat = 0.3 × 0.336 MJ

        = 0.3 × 0.336 × 10⁶

        = 100,800 Jkg


6 0
4 years ago
PLZ HELP!!!!
noname [10]
I believe the answer would be B) ...... sorry if i'm wrong
4 0
3 years ago
Read 2 more answers
This is “Fusion Reactions”.<br> Please answer number 8. Thank you.
Angelina_Jolie [31]

Answer:

²₁H + ³₂He —> ⁴₂He + ¹₁H

Explanation:

From the question given above,

²₁H + ³₂He —> __ + ¹₁H

Let ⁿₐX be the unknown.

Thus the equation becomes:

²₁H + ³₂He —> ⁿₐX + ¹₁H

We shall determine, n, a and X. This can be obtained as follow:

For n:

2 + 3 = n + 1

5 = n + 1

Collect like terms

n = 5 – 1

n = 4

For a:

1 + 2 = a + 1

3 = a + 1

Collect like terms

a = 3 – 1

a = 2

For X:

n = 4

a = 2

X =?

ⁿₐX => ⁴₂X => ⁴₂He

Thus, the balanced equation is

²₁H + ³₂He —> ⁴₂He + ¹₁H

8 0
3 years ago
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