1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olganol [36]
3 years ago
15

1. How many paths through which charge can flow would be shown in a diagram of a series

Physics
1 answer:
Elanso [62]3 years ago
5 0
1. One
2. Oohm


Hope this helps
You might be interested in
An object initially at rest experiences an acceleration of 1.90 ­m/s² for 6.60 s then travels at that constant velocity for anot
borishaifa [10]

Answer:

The magnitude of the object's average velocity is 9.74 m/s (9.80 m/s without any intermediate rounding).

Explanation:

Hi there!

The average velocity is calculated as the displacement of the object divided by the time it takes the object to do that displacement.

The displacement is calculated as the distance between the final position of the object and the initial position. <u>In this problem</u>, the displacement is equal to the traveled distance because the object travels only in one direction:

a.v = Δx/t

Where:

a.v = average velocity.

Δx = displacement = final position - initial position

t = time

So, let's find the distance traveled while the object was accelerating. For that, we will use this equation:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

In this case, since the object is initially at rest, v0 = 0. If we place the origin of the frame of reference at the point where the object starts moving, then x0 = 0. So, the equation of the position of the object after a time t will be:

x = 1/2 · a · t²

x = 1/2 · 1.90 m/s² · (6.60 s)²

x = 41.4 m

The object traveled 41.4 m during the first 6.60 s.

Now, let's find the rest of the traveled distance.

When the velocity is constant, a = 0. Then, the equation of position will be:

x = x0 + v · t

Let's place now the origin of the frame of reference at the point where the object starts traveling at constant velocity so that x0 = 0:

x = v · t

The velocity reached by the object during the acceleration phase is calculated as follows:

v = v0 + a · t   (v0 = 0 because the object started from rest)

v = 1.90 m/s² · 6.60 s

v = 12.5 m/s

Then, the distance traveled by the object at a constant velocity will be:

x = 12.5 m/s · 8.50 s

x = 106 m

The total traveled distance in 15.1 s is (106 m + 41.4 m) 147 m.

Then the displacement will be:

Δx = final position - initial position

Δx = 147 m - 0 = 147 m

and the average velocity will be:

a.v = Δx/t

a.v = 147 m / 15.1 s

a.v = 9.74 m/s

The magnitude of the object's average velocity is 9.74 m/s (9.80 m/s without any intermediate rounding).

8 0
3 years ago
Group 18 noble gases are inert because
hammer [34]

Answer:

d.

Explanation:

have a full 8 electrons on the outermost ring

4 0
3 years ago
Question 14 of 25
natali 33 [55]

the answer is sueist

Explanation:

7 0
3 years ago
Read 2 more answers
How do prokaryotic cells replicate?
Alika [10]

Answer:

The usual method of prokaryote cell division is termed binary fission. The prokaryotic chromosome is a single DNA molecule that first replicates, then attaches each copy to a different part of the cell membrane. When the cell begins to pull apart, the replicate and original chromosomes are separated.

6 0
3 years ago
On which date is the gravitational force between Earth and the moon the greatest?
Genrish500 [490]

The gravitational forces between the Earth and Moon are greatest when the two bodies are closest together. That happens every 27.32 days, when the Moon is at the perigee of its orbit.

Even if this happened at the same time in every orbit, the date would change, because there are not 27.32 days in a month.

But it doesn't happen at the same time in every orbit ... the Moon's perigee precesses around its orbit, on account of the gravitational forces toward the Earth, the Sun, Venus, Mars, and the other planets.

3 0
3 years ago
Other questions:
  • A 1.34 kg ball is connected by means of two massless strings, each of length L 1.70 m, to a vertical, rotating rod. The strings
    13·1 answer
  • An electric heater draws 13 amperes of current when connected to 120 volts. If the price of electricity is $0.10/kWh, what would
    10·1 answer
  • An object is moving along a straight line. The graph shows the velocity of the object over
    8·2 answers
  • An object of mass 4 kg is initially at rest on a frictionless ice rink. It suddenly explodes into three pieces (I have no idea w
    12·1 answer
  • You notice the flagpole at school vibrating in the breeze. You count the vibrations and find that
    11·1 answer
  • Find the net work done by friction on the body of a snake slithering in a complete circle of 1.04 m radius. The coefficient of f
    5·1 answer
  • Two point-charges Q1 and Q2 are 2.5 m apart, and their total charge is 19μC. If the force of repulsion between them is 0.07 N,
    10·1 answer
  • A standing wave with a fundamental frequency 1.25x10 2 Hz is set up on a string of length 0.750 meters. What is the frequency of
    6·1 answer
  • What impulse will be given to an object if it experiences a force of 0.5 N for 30 seconds
    13·1 answer
  • Is the normal force equivalent to the weight of an object?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!