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olganol [36]
3 years ago
15

1. How many paths through which charge can flow would be shown in a diagram of a series

Physics
1 answer:
Elanso [62]3 years ago
5 0
1. One
2. Oohm


Hope this helps
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Which of the following is a Nobel gas?<br> Ba2+<br> OA<br> OB. Ci<br> Kr<br> Ос.<br> Ca<br> D.
stepan [7]

Answer:

Kr

Explanation:

the element that is in group 18 is noble gasses. the elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

5 0
3 years ago
What is the current in milliamperes produced by the solar cells of a pocket calculator through which 3.70 C of charge passes in
Kaylis [27]

Answer:

Current flowing in the cell will be equal to 0.1284 mA

Explanation:

We have given charge q = 3.70 C

And time through which charge is flowing = 8 hour

We know that 1 hour = 60 minutes, and 1 minute = 60 sec

So 1 hour = 60×60 = 3600 sec

So 8 hour = 8×3600 = 28800 sec

We know that current is rate time rate of flow of charge

So current i=\frac{q}{t}=\frac{3.70}{28800}=1.284\times 10^{-4}A=0.1284mA

So current flowing in the cell will be equal to 0.1284 mA

3 0
4 years ago
A car begins at rest (0 velocity), 5 seconds later it is travelling at 20 meters/per second. What was the acceleration of the ve
klasskru [66]

use the formula

v= u+ at

v is final velocity , u is initial velocity , a is acceleration and t is time

put the values

20 = 0+ a×5

a = 4 m/s²

4 0
3 years ago
Read 2 more answers
Gasoline burns in the cylinder of an automobile engine. During the combustion reaction, the production of gas forces the piston
serg [7]

Answer:

\Delta U = 1640 J

Explanation:

As we know by first law of thermodynamics that for ideal gas system we have

Heat given = change in internal energy + Work done

so here we will have

Heat given to the system = 2.2 kJ

Q = 2200 J

also we know that work done by the system is given as

W = 560 J

so we have

\Delta U = Q - W

\Delta U = 2200 - 560

\Delta U = 1640 J

6 0
4 years ago
The internal energy of nmoles of an ideal gas depends on a. one state variable T.
VMariaS [17]

Answer:

Correct option a. one state variable T.

Explanation:

In the case of an ideal gas it is shown that internal energy depends exclusively on temperature, since in an ideal gas any interaction between the molecules or atoms that constitute it is neglected, so that internal energy is only kinetic energy, which depends Only of the temperature. This fact is known as Joule's law.

The internal energy variation of an ideal gas (monoatomic or diatomic) between two states A and B is calculated by the expression:

ΔUAB = n × Cv × (TB - TA)

Where n is the number of moles and Cv the molar heat capacity at constant volume. Temperatures must be expressed in Kelvin.

An ideal gas will suffer the same variation in internal energy (ΔUAB) as long as its initial temperature is TA and its final temperature TB, according to Joule's Law, whatever the type of process performed.

3 0
3 years ago
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