Answer:
n = 0.207 mole
Explanation:
We have,
P = 1 atm
V = 5 liter
R = 0.0821 L.atm/mol.K
T = 293 K
We need to find the value of n. The relation is as follows :
PV = nRT
Solving for n,
So, the value of n is 0.207 mol.
Answer:
Molecular Formula = C₆H₁₂O₆
Solution:
Molecular formula is calculated by using following formula,
Molecular Formula = n × Empirical Formula ---- (1)
Also, n is given as,
n = Molecular Weight / Empirical Formula Weight
Molecular Weight = 180.2 g.mol⁻¹
Empirical Formula Weight = 12 (C) + 2 (H₂) + 16 (O) = 30 g.mol⁻¹
Son
n = 180.2 g.mol⁻¹ ÷ 30 g.mol⁻¹
n = 6
Putting Empirical Formula and value of "n" in equation 1,
Molecular Formula = 6 × CH₂O
Molecular Formula = C₆H₁₂O₆
Answer:
The coefficients in order are 2, 1, 1
Explanation:
Each side of the reaction needs to have the same number of each element due to conservation of matter.
First I looked at what was uneven, notice there are 2 Na on the left side and 4 Na on the left. The easiest way to fix that is to add a 2 on the Na2HPO4:
2(Na2HPO4)--> Na4P2O7 + H2O
Next take count of each element on both sides to see if the 2 balanced everything:
On the left there are 4 Na, 2 H, 2 P, and 8 O
On the right there are 4 Na, 2 H, 2 P, and 8 O
Since both sides match, you are done!
A 200 what? Then I can help!
For Ca(OH)2, Ksp = [Ca2+][OH-]^2
You have your Ksp as 6.5 x 10^-6. Your [OH-] comes almost entirely from the 0.10 mol of NaOH, since Ca(OH)2 barely dissolves. Your [OH-] is therefore 0.10 M (since you have 1 L of solution).
6.5 x 10^-6 = [Ca2+](0.10)^2
Solve for [Ca2+]:
6.5 x 10^-6 / (0.10)^2 = [Ca2+]
[Ca2+] = 0.00065 M
The maximum concentration of [Ca2+] is 0.00065 M, and you have 0.0010 M Ca(OH)2, so you’ll end up with 0.00065 M Ca2+ in solution.
