2C4H10 + 13O2 -> 8CO2 + 10H2O
C: condensation
Examples are glasses fogging up and water droplets on a can of soda when it’s hot
Answer:
1. 0.023 M H3O+.
2. pOH = 5.52.
3. pH=9.45
4. 0.0018 M OH-
Explanation:
Hello,
In this case, such order could be computed by means of the pH, the lower the pH the more acid the solution, thus:
1. 0.0018 M OH-:
2. 0.023 M H3O+
3. pH=9.45
4.
Therefore the order is
1. 0.023 M H3O+.
2. pOH = 5.52.
3. pH=9.45
4. 0.0018 M OH-
Best regards.
First you have to look at the mole ratios of the reactants and products and that ratio is 2:2:2 or you can reduce that to 1:1:1. That means an amount of peroxide will produce the same amount of oxygen gas. If there are 8 mol of peroxide will give 8 mol of oxygen gas
The rate constants, K, can be expressed in many different terms. In this case, Kp is the equilibrium constant expressed in terms of gas partial pressure. The formula for this is:
Kp = [P(product C) × P(product D)] / [P(reactant A) × P(reactant B)]
As there is only one product, we will use only its pressure in the numerator.
Kp = [P(COCl2)] / [P(CO) × P(Cl2)]
P(COCl2) = 1.49 × 10⁸ × 2.22 × 10⁻⁴ × 2.22 × 10⁻⁴
P(COCl2) = 7.34 atm
