Boiling point ..................................................
The structure of Dimethyl sulfide is H3C-S-CH3. It is produced naturally by some marine algae.
<u>Explanation:</u>
- DMS or dimethyl sulfide is formed by using two methyl groups combined with one sulfur atom. It is an organosulphur compound with a structural formula H3C-S-CH3.
- Most abundant biological sulfur compounds emitted to air and oceans by phytoplankton.
- DMS is produced naturally by the waste of dimethyl sulphoxide which is disposed into the sewer causing environmental odor problems.
- It is a flammable liquid that boils at 37 degrees celsius and a disagreeable smell produced from the cooking of certain vegetables also indicates bacterial contamination in the production of malt and brewing.
Answer:
Solids: definite shape and definite volume (highest density)
Liquid: indefinite shape and definite volume (glide past each other)
Gas: indefinite shape and indefinite volume (lowest density)
Explanation:
look at the answer
Answer:
\left \{ {{y=206} \atop {x=82}}Pb \right.
Explanation:
isotopes are various forms of same elements with different atomic number but different mass number.
Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are
- Alpha particle emission \left \{ {{y=4} \atop {x=2}}He \right.
- Beta particle emission \left \{ {{y=0} \atop {x=-1}}e \right.
- gamma radiation \left \{ {{y=0} \atop {x=0}}γ \right.
in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.
Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below
\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right + \left \{ {{y=0} \atop {x=0}}γ\right.
Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right
