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elena55 [62]
4 years ago
13

9. According to an "alternative theory", H2O is

Chemistry
1 answer:
Jlenok [28]4 years ago
6 0

Answer:(4) ----accepts  a proton

Explanation:

H2O water can produce both hydrogen and   hydroxide ions

H2O --> H+ + OH-

According to the Bronsted-Lowry theory, it can be a proton donor and a proton acceptor.this means that It can donate a hydrogen ion to become its conjugate base, or  can accept a hydrogen ion to form its conjugate acid,

When , a water molecule, H2O accepts a proton it will act as a Brønsted-Lowry base especially when dissolved in a strong acidic medium. for eg

HCl + H2O(l) → H3O+(aq) + Cl−(aq)

Here, Hydrochloric acid is a strong acid and ionizes completely in  water, since it is more acidic than water, the water will act as a base.

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66.667 mL of 3.000 M H2SO4 (aq) solution was neutralized by the stoichiometric amount of 4.000 M Al(OH)3 solution in a coffee cu
Alik [6]

Answer:

\large \boxed{\Delta_{\textbf{r}}H =\text{-4600 J$\cdot$ mol}^{-1}}

Explanation:

This is an unrealistic problem, because Al(OH)₃is highly insoluble in water.

There are two parts to this question:

A. Stoichiometry — in which we figure out the volumes, masses, and moles of products

B. Calorimetry     — in which we calculate the enthalpy of reaction.

A. Stoichiometry

1. Calculate the volume of Al(OH)₃  

(a) Balanced chemical equation.

               2Al(OH)₃ + 3H₂SO₄ ⟶ Al₂(SO₄)₃+ 6H₂O

V/mL:                          66.667

c/mol·L⁻¹:   4.000        3 .000

(b) Moles of H₂SO₄

\rm \text{66.667 mL H$_{2}$}SO_{4} \times \dfrac{\text{3.000 mmol H$_{2}$SO}_{4}}{\text{1 mL H$_{2}$SO}_{4}} = \text{200.00 mmol H$_{2}$SO}_{4}

(c). Moles of Al(OH)₃

The molar ratio is 2 mmol Al(OH)₃:3 mmol H₂SO₄

\text{Moles of Al(OH)}_{3} =  \text{200.00 mmol of H$_{2}$SO}_{4} \times \dfrac{\text{2 mmol Al(OH)}_{3}}{\text{3 mmol H$_{2}$SO}_{4}}\\\\= \text{133.33 mmol Al(OH)}_{3}

(d). Volume of Al(OH)₃

\text{Moles of Al(OH)}_{3} =  \text{200.00 mmol of H$_{2}$SO}_{4} \times \dfrac{\text{1 mL Al(OH)}_{3}}{\text{4 mmol H$_{2}$SO}_{4}} = \text{50.000 mL Al(OH)}_{3}

B. Calorimetry

There are two energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm calorimeter

 q₁   +    q₂     = 0

nΔH + mCΔT = 0

Data:

Moles  of Al₂(SO₄)₃ = 0.066 667 mol

C = 1.10 J°C⁻¹g⁻¹

T_i = 22.3 °C

T_f = 24.7 °C

Calculations

(a) Mass of solution

Assume the solutions have the same density as water (unrealistic).

Mass of sulfuric acid solution                =   66.667 g  

Mass of aluminium hydroxide solution = <u>  50.000    </u>

                                                   TOTAL =  116.667 g

(b) ΔT

ΔT = T_f - Ti = 24.7 °C - 22.3 °C = 2.4°C

(c) ΔH

\begin{array}{ccccl}n\Delta H & +& mC \Delta T& = &0\\\text{0.066 667 mol }\times \Delta H& + & \text{116.667 g} \times 1.10 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 2.4 \, ^{\circ}\text{C} & = & 0\\0.066667 \Delta H \text{ mol} & + & \text{310 J} & = & 0\\&&0.066667 \Delta H \text{ mol} & = & \text{-310 J} & & \\\end{array}\\

\begin{array}{ccccl}& &\Delta H & = & \dfrac{\text{-310 J}}{\text{0.066667 mol}}\\\\& &\Delta H & = & \textbf{-4600 kJ/mol}\\\end{array}\\\large \boxed{\mathbf{\Delta_{\textbf{r}}H} =\textbf{-4600 J$\cdot$ mol}^{\mathbf{-1}}}

This is an absurd answer, but it's what comes from your numbers.

6 0
3 years ago
What is the amount, in mol, of 15g of carbonate ions, C03^2-​
Brilliant_brown [7]

24 electrons.............

8 0
3 years ago
What do the brackets in chemical equations mean?
Alex777 [14]
The bracket just separate an atom or the ion and in the above it means there are two hydroxide molecules
so bracket function is just to  separate ions and molecules
hope it helps
7 0
3 years ago
Please Help me!!<br> Match the definition to the location on the Venn Diagram
frozen [14]
The answer is 123
Brainliest??

 
5 0
4 years ago
What type of bond is Na3PO4?; Is Na3PO4 ionic or molecular?; Does Na3PO4 have ionic and covalent bonds?; Is Na3PO4 a polyatomic
Leni [432]

The type of the bond is present Na₃PO₄ is the ionic bond. the Na₃PO₄ is the ionic compound. yes the Na₃PO₄ is the polyatomic ion.

The Na₃PO₄ is Na⁺  and PO₄³⁻. the phosphorus is the non metal and the oxygen atom  is the non metal. the non meta and non meta form the covalent or molecular bond. the bond between the PO₄³⁻ bond is the covalent bond but the overall present in the Na₃PO₄ is the ionic bond . the bons in between the Na⁺  and PO₄³⁻ is the the ionic bond. the PO₄³⁻ id the polyatomic ion .

The bond between the positively charged ion and the negatively charged ion are called as the ionic bond and the compound form is the ionic compound.

To learn more about ionic bond here

brainly.com/question/29005103

#SPJ4

6 0
1 year ago
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