Answer:
V KOH = 41 mL
Explanation:
for neutralization:
∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L
∴ V H2SO4 = 41 mL = 0.041 L
∴ <em>C</em> KOH = 0.0050 N = 0.0050 eq-g/L
∴ E KOH = 1 eq-g/mol
⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L
⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH
⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)
⇒ V KOH = 0.041 L
well she can test both of the soap by putting one on and plate and another on the other plate and which ever is cleaner is your answer
See the image below-⬇⬇-
Hope this helps :D
PART A
3. A cylinder of compressed gas has a pressure of 4.882 atm on one day. The next
day, the same cylinder of gas has a pressure of 4.690 atm, and its temperature is
8°C. What was the temperature on the previous day in °C? Ans: 20°C.
