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RUDIKE [14]
3 years ago
8

How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?

Chemistry
1 answer:
Kipish [7]3 years ago
4 0

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

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Imporance of mixture in our daily life​
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Explanation:

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How is gravity an attractive force?
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5 0
3 years ago
Read 2 more answers
What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
tatiyna

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

6 0
3 years ago
What mass of NaOH do you need to dissolve in 500ml of solution to obtain a 0.6mol / l solution?
lara31 [8.8K]

Mass of NaOH required = 12 g

<h3>Further explanation</h3>

Given

500 ml solution = 0.5 L

Molarity = 0.6 mol / L

Required

mass of NaOH

Solution

Molarity = moles of solute per liter of solution

M = n / V

solute = NaOH

moles of solute = n  =  M x V

n = 0.6 x 0.5

<em>n = 0.3 moles</em>

Mass of NaOH = mol x MW

mass = 0.3 x 40 = 12 g

3 0
3 years ago
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