X^2 +8 =0 please show all work

1 answer:

6 0

$x^2+8=0\\
x^2=-8\\
x=-\sqrt{-8} \vee x=\sqrt{-8}\\
x=-\sqrt{8\cdot(-1)} \vee x=\sqrt{8\cdot(-1)}\\
x=-\sqrt{8}\cdot\sqrt{-1} \vee x=\sqrt{8}\cdot\sqrt{-1}\\
x=-\sqrt{4}\cdot \sqrt2\cdot i \vee x=\sqrt{4}\cdot \sqrt 2\cdot i\\
x=-2\sqrt{2}i \vee x=2\sqrt{2}i
$

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Answer:

width is 8 length is 4

Step-by-step explanation:

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pogonyaev

Answer:

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Step-by-step explanation:

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$\bf ~~~~~~~~~~~~\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------$

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Answer:

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