All categories

3 years ago

X^2 +8 =0 please show all work

1 answer:

6 0

$x^2+8=0\\
x^2=-8\\
x=-\sqrt{-8} \vee x=\sqrt{-8}\\
x=-\sqrt{8\cdot(-1)} \vee x=\sqrt{8\cdot(-1)}\\
x=-\sqrt{8}\cdot\sqrt{-1} \vee x=\sqrt{8}\cdot\sqrt{-1}\\
x=-\sqrt{4}\cdot \sqrt2\cdot i \vee x=\sqrt{4}\cdot \sqrt 2\cdot i\\
x=-2\sqrt{2}i \vee x=2\sqrt{2}i
$

You might be interested in

Please answer this question I need this urgent Help meeeee

iren [92.7K]

Answer:

$\frac{s}{2t}$

Step-by-step explanation:

When you have exponents above a like term and they are being multiplied together, you add them.

For example:

$a^{x} *a^{y} = a^{x + y}$

So let's group like terms in the numerator:

$4r^{3} r^{-5} s^{-2} s^{-1}t$ We can add terms like in the example.

$4 r^{-2} s^{-3} t$

Let's rearrange the denominator.

$8r^{-2} s^{-4} t^{2}$

Now we have:

$\frac{4r^{-2} s^{-3}t}{8 r^{-2} s^{-4} t^{2} }$ Cancel like terms

4/8 = 1/2

$r^{-2} /r^{-2}$ = 1 So it cancels

$s^{-3} / s^{-4} = s^{-1}$ = s Since s is raised to the -1 it goes on top and becomes s.

$t / t^{2} = 1/t$

Now we combine everything back together:

$\frac{s}{2t}$

8 0

3 years ago

3. Please help me with this question

bagirrra123 [75]

Answer:

Step-by-step explanation:

Multiply the exponents together

6 0

3 years ago

Find the median of the following set of data:

Troyanec [42]

Answer:

Step-by-step explanation:

The median is the middle value of the data set in ascending order. If there is no exact middle value then it is the average of the values either side of the middle.

Arrange the data in ascending order

48, 52, 54, 57, 57, 57, 61, 61, 65

↑

The median of the data set is 57 → b

3 0

3 years ago

Write a number that has four digits with the same number in all places such as 4444 circle the digit with the greatest value und

joja [24]

For example you can take the number 7 7 7 7

(7)77{7}

The first seven is the greatest it's 7,000

The last seven is the least its 7

HOPE THIS HELPS!!!

4 0

3 years ago

Find f(-1) if f(x) = -2x^2 -x

kykrilka [37]

I hope it was helpful to you

if u like follow me

3 0

2 years ago