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sasho [114]
3 years ago
14

Even though we have known of many nuclear energy technologies for about one century some of these technologies have not yet been

fully developed. Obtaining energy from thorium remains a challenge for many reasons. In a reactor, thorium is bombarded with neutrons and becomes U-233 and then U-234, which can undergo fission and produce energy. Complete the following U-234 fission reaction. Hint: Do not ignore the amount of energy given off by the reaction! 234.0 tlu . i37 154Xe + 3?Sr + 3 1.0087n + 180 MeV
Chemistry
1 answer:
Romashka [77]3 years ago
7 0

<u>Answer:</u> The nuclear fission reaction of U-234.043 is written below.

<u>Explanation:</u>

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

^{234.043}_{92}\textrm{U}\rightarrow ^{137.159}_{54}\textrm{Xe}+^{A}_{38}\textrm{Sr}+3^{1.0087}_0\textrm{n}+180MeV

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

234.043 = 137.159 + A + 3(1.0087)

A = 93.858

Now, the chemical equation becomes:

^{234.043}_{92}\textrm{U}\rightarrow ^{137.159}_{54}\textrm{Xe}+^{93.858}_{38}\textrm{Sr}+3^{1.0087}_0\textrm{n}+180MeV

Hence, the nuclear fission reaction of U-234.043 is written above.

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Explanation:

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Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
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Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

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