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hichkok12 [17]
3 years ago
5

Which model of the solar system is shown here?

Chemistry
2 answers:
Alisiya [41]3 years ago
8 0

Answer: C

Explanation: hope this helps

Rus_ich [418]3 years ago
5 0
I’m pretty sure it’s c too
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Most reactive<br> O Be<br> O Mg<br> O Ba<br> o Ca<br> Which one is the most reactive
katen-ka-za [31]

Answer:

Mg

Explanation:

I think the answer is Mg

7 0
3 years ago
iron has a density of 7.86 g cm3 could a block of metal with a mass of 18.2 and a volume of 2.56 cm^3 be iron?
satela [25.4K]

The density of the block will be "7.11 gm/cm³". A further explanation is provided below.

Given values are:

Density of iron,

  • 7.86 \ g/cm^3

Mass of block of metal,

  • 18.2 \ gm

Volume of block,

  • 2.56 \ cm^3

By using the formula,

→ Density = \frac{Mass}{Volume}

then,

→ The density of block will be:

= \frac{Mass}{Volume}

= \frac{18.2}{2.56}

= 7.11 \ gm/cm^3

Learn more:

brainly.com/question/10804879

7 0
3 years ago
33. Hydrocarbons that release pleasant odors are called_________<br> hydrocarbons. (1 point)
olya-2409 [2.1K]

Answer:

Aromatic Hydrocarbons

Explanation:

Aromatic (Pleasant Odour) Hydrocarbons are those having pleasant odours.

8 0
3 years ago
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When one carbon atom is bonded with several other carbon atoms in a single line, then how is the structure described?
Solnce55 [7]
Its described as a Straight Branch, hope this helps :)
3 0
3 years ago
Five ?L of a 10-to-1 dilution of a sample were added to 5mL of Bradford reagent. The absorbance at 595 nm was 0.78 and,according
Tomtit [17]

Answer:

0.03g/mL

Explanation:

Given parameters include:

Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL

Dilution factor = 10-to-1

The absorbance at 595 nm was 0.78

Mass of the diluted sample = 0.015 mg

We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.

So, to determine the concentration of the diluted sample, we have:

concentration of diluted sample = \frac{mass}{volume}

= \frac{0.015 mg}{ 5 \alpha L}   (where ∝ was use in place of μ in the expressed fraction)

= 0.003 mg/μL

The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:

protein concentration of the original solution = 10 × concentration of the diluted sample.

= 10  × 0.003 mg/μL

= 0.03 mg/μL

= \frac{0.03*10^{-3g}}{10^{-3}mL}

= 0.03g/mL

Hence, the protein concentration of the original solution is known to be  0.03g/mL

8 0
3 years ago
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