p(x) = 2x2 – 4x and q(x) = x – 3, what is (p•q)(x)
Solution:
Here we have to find p(q(x))
q(x) =x -3
we will plug value of q(x) in x of p(x)
p(x) =2x2-4x
p(q(x)) = 2(x-3)2-4(x-3)
= 2(x2-6x+9)-4(x-3)
=2x2-12x+18 -4x+12
=2x2-16x+30
Sorry if I am wrong I really am
Answer: Our function will be
Step-by-step explanation:
Since we have given that
Distance of the entrance = 180 meters
Speed of Nala who is running towards the entrance of the lair = 9.2
As we know the "Distance-Speed formula":
So, our required function will be
As we increase the time distance get reduced from 180 which is the distance of the entrance .
Hence, our function will be
Answer:
y = 2x - 10
Step-by-step explanation:
Put the equation in the form y = mx + b where m is the slope and b is the y-intercept. (For example, y = 3x + 1 would have a slope of 3 and a y-intercept of 1)
First, find the slope by doing change in y divided by change in x:
6 - 8 / 8 - 9 = -2 / -1 = 2
This means the slope is 2 and the equation would be
y = 2x + b
Then, since you know (9, 8) is a solution, you can plug x = 9 and y = 8 into that equation
8 = 2 * 9 + b
8 = 18 + b
b = -10
The equation is y = 2x - 10
All the pieces of rope are 7 feet long. you take 63 and divide it by 9.