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3 years ago

7

Newton’s first law says that if motion changes, then a force is exerted. Describe a collision in terms of the forces exerted on

both objects.

1 answer:

ira [324]3 years ago

4 0

Answer:

In collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

Explanation:

In a collision two objects, there is a force exerted on both objects that causes an acceleration of both objects. These forces that act on both objects are equal in magnitude and opposite in direction.

Thus, in collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

You might be interested in

Is a neutron star also a black hole?

coldgirl [10]

No. A neutron star is the weird remains of a star that blew its outer layers off
in a nova event, and then had enough mass left so that gravity crushed its
electrons into its protons, and then what was left of it shrank down to a sphere
of unimaginably dense neutron soup. But it didn't have enough mass to go
any farther than that.

A black hole is the remains of a star that had enough mass to go even farther
than that. No force in the universe was able to stop it from contracting, so it
kept contracting until its mass occupied no volume ... zero. It became even
more weird, and is composed of a substance that we don't know anything about
and can't describe, and occupies zero volume.

Contrary to popular fairy tales, a black hole doesn't reach out and "suck things in".
It's just so small (zero) that things can get very close to it. You know that gravity
gets stronger as you get closer to an object, so if the object has no size at all, you
can get really really close to it, and THAT's where the gravity gets really strong.
You may weigh, let's say, 100 pounds on the Earth. But you're like 4,000 miles
from the center of the Earth. What if all of the earth's mass was crammed into
the size of a bean. Then you could get 1 inch from it, and at that distance from
the mass of the Earth, you would weigh 25,344,000,000 pounds.
But Earth's mass is not enough to make a black hole. That takes a minimum
of about 3 times the mass of the sun, which is right about 1 million times the
Earth's mass. THEN you can get a lightweight black hole.
Do you see how it works now ?

I know. It all seems too fantastic to be true.
It sure does.

8 0

3 years ago

a bird is flying due east, it distance from a tall building is given by x(t) = 28m +(12.4m/s)t + (0.045 m/s^3)t^3. what is the i

lana66690 [7]

The instantaneous velocity is how the position is changing with respect to time in a specific point in time, as opposed to the average value given by Delta(x)/Delta(t). It's given by taking a limit of Delta(x)/Delta(t) where t approaches 0, that is, by derivating x(t) in respect to t.

v(t) = x'(t) = (28 + 12.4t + 0.045t^3)' = 12.4 + 0.135t^2

But we want to find the velocity at t = 8s:

v(8) = 12.4 + 0.135*(8)^2 = 21.04m/s

5 0

3 years ago

A student leaves a pencil on a desk and the pencil stays in the same spot until another student picks it up. Which law would tha

atroni [7]

The first law

In Newtons first law it states that an object will not change its motion unless a force acts upon it.

5 0

3 years ago

A real (non-Carnot) heat engine, operating between heat reservoirs at temperatures of and performs 4.1 kJ of net work, and rejec

Sati [7]

There are some missing data in the problem. The full text is the following:
"<span>A </span>real<span> (</span>non-Carnot<span>) </span>heat engine<span>, </span>operating between heat reservoirs<span> at </span>temperatures<span> of 710 K and 270 K </span>performs 4.1 kJ<span> of </span>net work<span>, and </span>rejects<span> 9.7 </span>kJ<span> of </span>heat<span>, in a </span>single cycle<span>. The </span>thermal efficiency<span> of a </span>Carnot heat<span> engine, operating between the same </span>heat<span> reservoirs, in percent, is closest to.."

Solution:
The efficiency of a Carnot cycle working between cold temperature </span> $T_C$ and hot temperature $T_H$ is given by
$\eta = 1 - \frac{T_C}{T_H}$
and it represents the maximum efficiency that can be reached by a machine operating between these temperatures. If we use the temperatures of the problem, $T_C=270 K$ and $T_H=710 K$ , the efficiency is
$\eta = 1 - \frac{270 K}{710 K}=0.62 = 62%$

Therefore, the correct answer is D) 62 %.

6 0

3 years ago

Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t

BabaBlast [244]

Answer:

$-\frac{8\pi}{3}rad/s^2$

Explanation:

To solve this problem we need to apply the concept related to Angular Acceleration. We can find it through the equation

$\omega_f^2-\omega_i^2=2\alpha\theta$

Where for definition,

$\omega_i = \frac{\theta}{t}$

The number of revolution $(\theta)$ was given by 20 times, then

$\omega_i = \frac{20*2pi}{5}$

$\omega = 8\pi rad/s$

We know as well that the salad rotates 6 more times, therefore in angle measurements that is

$\theta = 6*2\pi rad = 12\pi rad$

The cook at the end stop to spin, then using our first equation,

$0-8\pi = 2\alpha (12\pi)$

re-arrange to solve $\alpha$ ,

$\alpha = \frac{-8\pi}{2*12\pi}$

$\alpha = -\frac{8\pi}{3}rad/s^2$

We can know find the required time,

$\omega_f-\omega_i = \alpha t$

Re-arrange to find t, and considering that $\omega_f=0$

$t= \frac{\omega_i}{\alpha}$

$t=\frac{-8\pi}{-8\pi/3}$

$t=3s$

Therefore take for the salad spinner to come to rest is 3 seconds with acceleration of $-\frac{8\pi}{3}rad/s^2$

6 0

3 years ago

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