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3 years ago

I need to know how to do these so someone please work them out ASAP. Thank you.

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

5 0

Answer:

use a calculator the variable is the angle of a triangle

Step-by-step explanation:

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A local civic group is selling

dangina [55]

What’s the question

3 0

3 years ago

Hey, guys I really need help with this sooo... if one of you smart people can help me, please Its for 8th grade math

Licemer1 [7]

Answer:

(0,-1)

Step-by-step explanation:

x point is 6, and the translation is x - 6

6 - 6 = 0

x = 0

y point is 0 and translation is y - 1

0 - 1 = -1

y = -1

Coordinates are (0,-1)

If my answer is incorrect, pls correct me!

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-Chetan K

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3 years ago

Read 2 more answers

2x=5 what is the value of x?

natali 33 [55]

The answer is x = 2.5

Basically all you have to do is divide 5 by 2 and you got your answer

3 0

4 years ago

A box with a square base and open top must have a volume of 237276 cm^3. We wish to find the dimensions of the box that minimize

svp [43]

Answer:

$A(x)=\dfrac{x^3+949104}{x}$

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 237276 cubic centimetre. We want to find a formula for the surface area of the box in terms of only x, the length of one side of the square base.

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume,

$V=x^2h=237276\\\\h=\dfrac{237276}{x^2}$

Surface Area of the box = Base Area + Area of 4 sides

$Area, A(x,h)=x^2+4xh$

Substitute h derived above into A(x,h)

$Area=x^2+4x(\frac{237276}{x^2})\\\\A(x)=x^2+\dfrac{949104}{x}\\\\A(x)=\dfrac{x^3+949104}{x}$

Therefore, a formula for the surface area of the box in terms of only x, the length of one side of the square base is:

$A(x)=\dfrac{x^3+949104}{x}$

7 0

4 years ago

Write an equation of the line that passes through (3,1) and (3,5).Write in slope-int.form (y=mx+b)

ahrayia [7]

The answer: y2-y1
x2-x1

5-1
3-3

4 divide 0= 0
y=mx + b
y=0+b
0=0+b

b= 0

8 0

3 years ago