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RUDIKE [14]
3 years ago
9

How much TV do college students watch? A survey of 361 students recorded the number of hours of television they watched per week

. The sample mean was 6.504 hours with a standard deviation of 5.584. The standard error of the mean was 0.294. Find a 90% confidence interval for the population mean. Round your answer to three decimal places
Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer: 90% confidence interval would be (6.022,6.986).

Step-by-step explanation:

Since we have given that

Number of students = 361

Sample mean = 6.504

Sample standard deviation = 5.584

Standard error of the mean = 0.294

At 90% confidence level,

So, α = 0.01

So, z = 1.64

Margin of error is given by

z\times \text{Standard error}\\\\=1.64\times 0.294\\\\=0.48216

So, Lower limit would be

\bar{x}-0.482\\\\=6.504-0.482\\\\=6.022

Upper limit would be

\bar{x}+0.482\\\\=6.504+0.482\\\\=6.986

So, 90% confidence interval would be (6.022,6.986).

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A

Step-by-step explanation:

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3 years ago
The admission fee at the Smithsonian Air & Space
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6 0
2 years ago
Given that x = 7.4 m and 0 = 26°, work out AB rounded to 3 SF.
Vladimir [108]

Answer:

3.24m

Step-by-step explanation:

SOH

sin(26)=O/7.4

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7 0
3 years ago
In a group of college students, the ratio of men to women is 3:1 (i.e., 3 to 1). In a recent survey, 40% of the men in this grou
katovenus [111]

Answer:

0.3875

Step-by-step explanation:

Given that in a group of college students, the ratio of men to women is 3:1 (i.e., 3 to 1). In a recent survey, 40% of the men in this group selected hiking as their favorite outdoor activity whereas 35% of the women in the group selected hiking as their favorite outdoor activity

From the above information we find that

P(Men) = 0.75 and P(women) = 0.25 (since men:women = 3:1)

Out of men prob for not selecting hiking as their favorite outdoor activity

=1-0.6 = 0.4

Out of women prob for not selecting hiking as their favorite outdoor activity

=1-0.35 = 0.65

Prob for a randomly selected person that hiking is not his/her favorite outdoor activity = Prob (man and not selected activitiy) + P(women and not selected activity) (since men and women are mutually exclusive and exhaustive)

=0.75(0.4)+0.25(0.35)\\= 0.30+0.0875\\\\=0.3875

6 0
3 years ago
3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d
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Expand the right side:

(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)

=ab^2x^3-b^2cx^2-ad^2x+cd^2

Notice that 98 = 2 * 7 * 7, so we have c=2 and d=7.

Then

-ad^2=-147\implies a=\dfrac{147}{49}=3

and

ab^2=3\implies b^2=1\implies b=1

6 0
3 years ago
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