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viva [34]
3 years ago
7

Consider the following reaction at 298K.

Chemistry
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

Eªcell > 0; n = 2

Explanation:

The reaction:

I2 (s) + Pb (s) → 2 I- (aq) + Pb2+ (aq)

Is product favored.

A reaction that is product favored has ΔG < 0 (Spontaneous)

K > 1 (Because concentration of products is >>>> concentration reactants).

Eªcell > 0 Because reaction is spontaneous.

And n = 2 electrons because Pb(s) is oxidizing to Pb2+ and I₂ is reducing to I⁻ (2 electrons). Statements that are true are:

<h3>Eªcell > 0; n = 2</h3>
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Description of how the combined gas law must be modified to introduce the number of moles
telo118 [61]
So the ideal gas law is pv=nrt
The letter n stands for the number of moles. divide both side by rt to isolate.
pv/rt=n
8 0
3 years ago
How much concentrated 18M sulfuric acid is needed to prepare 250mL of a 6.0M solution?
slavikrds [6]
C₁ * V₁ = C₂ * V₂ 

18 * V₁ = 6.0 * 250

18 V₁ = 1500

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V₁ = 83.33 mL

hope this helps!


5 0
3 years ago
Which is the net result of the proton-proton chain? 6 protons = 2 heliums + 3 positrons + 3 neutrinos + gamma rays 4 protons = 1
saveliy_v [14]

Answer: 5.125 neutrinos

Explanation:

8 0
3 years ago
A hot air balloon is filled with 15 moles helium gas and 5 moles nitrogen gas. What is the volume of the balloon at 1.01 atm and
kvasek [131]

<u>Given:</u>

Moles of He = 15

Moles of N2 = 5

Pressure (P) = 1.01 atm

Temperature (T) = 300 K

<u>To determine:</u>

The volume (V) of the balloon

<u>Explanation:</u>

From the ideal gas law:

PV = nRT

where P = pressure of the gas

V = volume

n = number of moles of the gas

T = temperature

R = gas constant = 0.0821 L-atm/mol-K

In this case we have:-

n(total) = 15 + 5 = 20 moles

P = 1.01 atm and T = 300K

V = nRT/P = 20 moles * 0.0821 L-atm/mol-K * 300 K/1.01 atm = 487.7 L

Ans: Volume of the balloon is around 488 L


3 0
3 years ago
The specific heat of aluminum is 0.897j/(g•°C). If a 22.6 g sample of aluminum is heated from 25°C to 250°C, then how much heat
Oxana [17]

Q=mcat

=(22.6)(.897)(250-25)

4,561.245 or 4.5 * 10^-3

3 0
3 years ago
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