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viva [34]
3 years ago
7

Consider the following reaction at 298K.

Chemistry
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

Eªcell > 0; n = 2

Explanation:

The reaction:

I2 (s) + Pb (s) → 2 I- (aq) + Pb2+ (aq)

Is product favored.

A reaction that is product favored has ΔG < 0 (Spontaneous)

K > 1 (Because concentration of products is >>>> concentration reactants).

Eªcell > 0 Because reaction is spontaneous.

And n = 2 electrons because Pb(s) is oxidizing to Pb2+ and I₂ is reducing to I⁻ (2 electrons). Statements that are true are:

<h3>Eªcell > 0; n = 2</h3>
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Answer:

1) A transform boundary is a boundary plate in which the motion usually lies horizontal.

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5 0
3 years ago
If 316 mL nitrogen is combined with 178 mL oxygen, what volume of N2O is produced at constant temperature and pressure if the re
lord [1]

Answer;

=259 ml

Explanation;

-According to Gay Lussac's Law of Combining Volumes when gases react, they do so in volumes which have a simple ratio to one another, and to the volume of the product formed if gaseous, provided the temperature and pressure remain constant.

-Thus; from the volume of nitrogen and oxygen gases; we have; 316 / 178 = 1.775 moles of nitrogen gas per mole of oxygen gas.

-Therefore, nitrogen gas is the limiting reactant, and for each mole of nitrogen gas used, we will get 1 mole of N2O. This means the resulting volume of N2O with 100% yield will be the same as the volume of nitrogen gas used, thus, 100% yield will produce 316 mL.

However, with 82% yield the volume would be; 316 × 82/100 =259 ml

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7 0
3 years ago
Read 2 more answers
Need help please help me
Mademuasel [1]

Answer:

The answer is most likely compound a

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Covalent compounds have low melting and boiling points and conduct electricity poorly

8 0
3 years ago
An oxide of nitrogen contain its own volume of nitrogen
kirill115 [55]

Answer:

NO2 is the molecular formula  of nitrogen Oxide​

Explanation:

Correct question

An oxide of nitrogen contain its own volume of nitrogen

its vapour dentity is 23. Find the molecular formula

Of nitrogen Oxide

Solution

As we know

Molecular Weight  is equal to two times the  vapour density

Hence, the molecular weight of Oxide of nitrogen is 2 * 22 = 44

Molecular weight of Oxide of nitrogen  is the sum of atomic weight of nitrogen and oxygen

Molecular weight of Oxide of nitrogen = 14 + 16 *Y

14 + 16 *Y  = 46

Y = 2

Hence, the formula is NO2

4 0
3 years ago
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blsea [12.9K]
Idk I think its a major addation Or Reading Or Socail Studies Sorry tho

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