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Anuta_ua [19.1K]
3 years ago
15

What is the name of group 5a

Chemistry
1 answer:
EastWind [94]3 years ago
5 0

Answer:

It is called <em>Pnictogens</em><em>.</em>

Explanation:

This word is fro a greek word called <em>p</em><em>n</em><em>i</em><em>g</em><em>e</em><em>i</em><em>n</em><em> </em>which means <em>c</em><em>h</em><em>o</em><em>k</em><em>i</em><em>n</em><em>g</em><em> </em>due to a choking property of <em>n</em><em>i</em><em>t</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em> </em><em>g</em><em>a</em><em>s</em><em> </em>when opposed to air with (oxygen).

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Answer:

C.

Fusion reactions require a lot of heat and pressure

Explanation:

nuclear fusion takes place only at extremely high temperatures. That's because a great deal of energy is needed to overcome the force of repulsion between the positively charged nuclei. ... A: Nuclear fusion doesn't occur naturally on Earth because it requires temperatures far higher than Earth temperatures.

4 0
3 years ago
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To explain the photoelectric effect, Albert Einstein linked the photoelectric effect to an idea from which scientist?
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8 0
3 years ago
Write the net ionic equation for the reaction of aqueous copper(II) chloride with aqueous sodium phosphate. Remember to include
sergeinik [125]

Answer:

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

Explanation:

Let's consider the molecular equation between aqueous copper(II) chloride and aqueous sodium phosphate.

3 CuCl₂(aq) + 2 Na₃PO₄(aq) ⇒ 6 NaCl(aq) + Cu₃(PO₄)₂(s)

The complete ionic equation includes all the ions and insoluble species.

3 Cu²⁺(aq) + 6 Cl⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇒ 6 Na⁺(aq) + 6 Cl⁻(aq) + Cu₃(PO₄)₂(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and insoluble species.

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

7 0
2 years ago
How many fluorine atoms are present in 125.0g of phosphorus pentafluoride?
vladimir2022 [97]

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125 g PF5 × (1 mol PF5/125.966 g PF5) = 0.992 mol PF5

0.992 mol PF5 × (6.022 × 10^23 molecules PF5);

= 5.97 × 10^23 molecules PF5

Since there 5 fluorine atoms per molecule of PF5,

(5.97.× 10^23 molecules PF5) × (5 atoms F/1 molecule PF5)

= 2.99 × 10^24 atoms F

8 0
3 years ago
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