Answer:
Explanation:
Hello!
In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:
Then, the liters of solution:
Finally, the molarity turns out:
Best regards!
Answer:
2.288 Moles of NH₄NO₃
Explanation:
The Balance chemical equation is as follow:
(NH₄)₂CO₃ + 2 HNO₃ → 2 NH₄NO₃ + H₂O + CO₂
To solve this problem we will do following steps:
Finding moles of Ammonium Carbonate:
As we know,
Moles = Mass / M.Mass
So,
Moles = 110 g / 96.08 g/mol
Moles = 1.144 moles
Calculating moles of Ammonium Nitrate:
According to balance chemical equation;
1 mole of (NH₄)₂CO₃ produces = 2 moles of NH₄NO₃
So,
1.144 moles of (NH₄)₂CO₃ will produce = X moles of NH₄NO₃
Solving for X,
X = 2 moles × 1.144 moles ÷ 1 mole
X = 2.288 moles of NH₄NO₃
I believe it is the third option :)
