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viva [34]
3 years ago
10

How many moles are in 45.8 g of calcium nitrate, Ca(NO3),?

Chemistry
1 answer:
Deffense [45]3 years ago
4 0

Answer:

the number of moles is 0.279

Explanation:

The calculation of the number of moles of calcium nitrate, is given  below;

As We know that

Number of moles = mass of substance ÷ molecular weight

where

Mass of substance is 45.8g

And, the molecular weight is 164.088

so,

= 45.8 g ÷ 164.088

= 0.279moles

Thus , the number of moles is 0.279

We simply used the above formula so that the accurate value could arrive

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Explanation:

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           OCl^{-} + I^{-} \rightarrow OI^{-1} + Cl^{-1}

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Hence, equation for rate law of reaction will be as follows.

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(b)  Since, the rate equation is as follows.

                    Rate = K [OCl^{-}][l^{-}]

Let us assume that ([OCl^{-}] = [l^{-}])

Putting the given values into the above equation as follows.

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                        = 6.52 \times 10^{5}

Therefore, rate when [OCl^{-}] = 1.8 \times 10^{3} M and [I^{-}]= 6.0 \times 10^{4} M is  6.52 \times 10^{5}.

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