The empirical and molecular formulas will be 
and 
respectively.
<h3>Empirical and molecular formula</h3>
The compound contains C, H, and O.
C = 61.15/12 = 5.0958
H = 5.3/1 = 5.3
O = 31.55/16 = 1.9719
Divide by the smallest
C = 2.6
H = 2.7
O = 1
Thus, the empirical formula is
Empirical formula mass = (12x5) + (1x5) + 16x2 = 97
n = 152.15/97 = 2
The molecular formula is
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Answer:
D
Explanation:
A weak acid and a strong base will form a basic salt.
Option A is acidic, this pH would be found in salts formed from reactions between strong acids and weak bases.
B and C are neutral or close to neutral and as such will be formed from weak acids and weak bases, or strong acids and strong bases.
Answer:
Boiling point of the solution is 100.78°C
Explanation:
This is about colligative properties.
First of all, we need to calculate molality from the freezing point depression.
ΔT = Kf . m . i
As the solute is nonelectrolyte, i = 1
0°C - (-2.79°C) = 1.86 °C/m . m . 1
2.79°C / 1.86 m/°C = 1.5 m
Now, we go to the boiling point elevation
ΔT = Kb . m . i
Final T° - 100°C = 0.52 °C/m . 1.5m . 1
Final T° = 0.52 °C/m . 1.5m . 1 + 100°C → 100.78°C
Look at the liter man it’s a great way to learn how much every liquid measurement is
A chemestretic equation equation which is formed by h20 mc square hydrogen peroxide and the equation of cf6c7bu7c
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