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3 years ago

What is the pH if the [H+] is 10.25x10-7M?

Chemistry

1 answer:

Marysya12 [62]3 years ago

7 0

Answer:

5.99

Explanation:

-log(10.25x10^-7)

- Hope this helps! Please let me know if you need further explanation.

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A dull metal object has a density of 8.8 G/ML and a volume of 20 ML calculate the mass

Alex

Answer:

Mass = 0.000176 gram

Steps:

m = V × ρ

= 20 milliliter × 8.8 gram/cubic meter

= 2.0E-5 cubic meter × 8.8 gram/cubic meter

= 0.000176 gram

Explanation:

8 0

3 years ago

HELP.

Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) = 163.9 grams ≈ 164 grams

The mass of tin is 164 grams

4 0

3 years ago

A photon with 2.3 eV of energy can eject an electron from potassium. What is the corresponding wavelength of this type of light?

Ira Lisetskai [31]

Answer:

$\lambda=540.16\ nm$

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy = $2.3\times 1.60\times 10^{-19}\ J=3.68\times 10^{-19}\ J$

Considering

$Energy=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light being bombarded

Thus,

$3.68\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\frac{3.68}{10^{19}}=\frac{19.878}{10^{26}\lambda}$

$3.68\times \:10^{26}\lambda=1.9878\times 10^{20}$

$\lambda=5.40163\times 10^{-7}\ m=540.16\times 10^{-9}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=540.16\ nm$

3 0

4 years ago

For Lewis acids and bases, the base is defined as an electron pair donor / acceptor (circle the correct answer).

damaskus [11]

Answer: electron donor.

Explanation:

According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions $(OH^-)$ when dissolved in water and an acid is defined as a substance which donates hydronium ions $(H_3O^+)$ in water.

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

$NH_3+H^+\rightarrow NH_4^+$

Here $NH_3$ acts as lewis base and $H^+$ act as lewis acid.

Thus lewis base is defined as an electron pair donor.

8 0

4 years ago

Mars to see if those environments can support life. Living organisms have needs in order to survive. One of those needs is the r

klemol [59]

They are trying to answer a question

3 0

3 years ago