The answer is 4.85, rounded
Answer:
39 touchdowns and 13 fieldgoals
Step-by-step explanation:
Let t= touchdowns
f = fieldgoals
They scored 35 times
t+f = 35
Touchdown is 7 pts and fieldgoal is 3 pt
7t+3f = 193
Multiply the first equation by-7
-7t -7f =-245
Add this to the second equation
-7t -7f =-245
7t+3f = 193
----------------------
-4f =-52
Divide by -4
-4f/-4 = -52/-4
f = 13
Now we can find t
t+f = 35
t+13 = 52
Subtract 13 from each side
t+13-13 =52-13
t =39
Answer:
I don't know what you are saying for solve for x though if your saying simplify
simplify answer: -9
If 2(3x-6) = 3 (2x-1) answer: No solution
If 2(3x-6) = -3 (2x-1) answer: x = 1.25
Step-by-step explanation:
Notice that
(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>
So we can add 1 to both sides of both equations, and we use the property above to get
<em>a</em> + <em>b</em> + <em>a b</em> = 76 ==> (1 + <em>a</em>)(1 + <em>b</em>) = 77
and
<em>c</em> + <em>d</em> + <em>c d</em> = 54 ==> (1 + <em>c</em>)(1 + <em>d</em>) = 55
Now, 77 = 7*11 and 55 = 5*11, so we get
<em>a</em> + 1 = 7 ==> <em>a</em> = 6
<em>b</em> + 1 = 11 ==> <em>b</em> = 10
(or the other way around, since the given relations are symmetric)
and
<em>c</em> + 1 = 5 ==> <em>c</em> = 4
<em>d</em> + 1 = 11 ==> <em>d</em> = 10
Now substitute these values into the desired quantity:
(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000
