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nikdorinn [45]
4 years ago
7

The retina is a photosensitive tissue that contains the special photoreceptor cells. What is the purpose of these photoreceptor

cells?
Question 19 options:


to convert light to electrical impulses


to invert the image right-side up again


to focus light waves on the back wall of the eye


to convert black and white into color

Chemistry
1 answer:
RideAnS [48]4 years ago
5 0
I am also taking the test, but I think it's C. But I'm not exactly sure
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5400 L to KL<br> With work??
Gnesinka [82]

Answer:

5.4KL

Explanation:

Divide by 1000

3 0
3 years ago
How do forensic scientists determine the time of death? There are timely pieces of evidence that help scientists with this task.
UNO [17]

I have done some research as well as asking some friends. This is what I came up with. Not sure if it is 100% correct.

step = time after death

1. Livor Mortis = 20-30 minutes

2. Eyes film (cloud) = 2 hours

3. Rigor Mortis begins = 4-6 hours

4. Empty small intestines = 12 hours

5. Bloating = 3-5 days

6. Decay

8 0
3 years ago
5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
While viruses are not living organisms, they do share some characteristics with living organisms such as bacteria and fungi. Whi
Rufina [12.5K]

viruses are made of proteins and contain genetic information to produce more of them in the form of DNA or RNA.

7 0
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Which of the following is an organic compound? carbon monoxide (CO) sodium chloride (NaCl) sulfur oxide (SO) water (H2O)
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The answer should be water (H2O)


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