Answer:
The moles of KClO3 = 0.052 moles
Explanation:
Step 1: Calculate the pressure of oxygen gas
The oxygen has a total pressure (including water vapour) of 760 mmHg
The pressure of Oxygen = (760 - 26) mmHg
= 734 mmHg of water vapor
Step 2: Calculate the no of moles of oxygen
Using Ideal gas equation
P V = n R T
P = pressure of oxygen in N/m2 ( you should convert 734 mmHg to pascal or N/m2) = 97,858.6 N/m2 or pas
V = 2 litres = 0.002 m3
R = gas constant = 8.31
T= 27oC = 300 K
Applying this equation P V = n R T
97,858.6 x 0.002 = n x 8.31 x 300
n = 0.0785 mol of Oxygen
From the balanced equation
2 KClO 3 ---- 2 KCl + 3 O 2
3 moles of oxygen is produced from 2 moles KClO3
so 0.0785 mole of oxygen will be produced from x
x = (0.0785 x 2 ) / 3
x = 0.052 moles of KClO3
6+2=115 and its good it took test
Weeks = 6 x 4 = 24
Mass leak rate of freon = 41.60 g/week
Mass leak rate of fluorine
Fluorine mass in Freon
= —————————————- X leak rate
M.M. Of Freon
19 x 3
——— X 41.60 = 20.010 gm/week
118.5
Total leaked in 6 months
= 24 x 20.010 = 480.24 gm = 0.480 Kg
The molecular mass of the compound CO2 is calculate by simply taking the number of atoms of each element and multiplying it by the molar mass of the element on the periodic table.
C = 1 • 12.0 g/mol
O2 = 2 • 16.0 g/mol = 32.0 g/mol
CO2 = 12.0 + 32.0 = 44.0 g/mol.
The formula mass of CO2 is 44.0 g/mol.
