Answer:
1.58 M
Explanation:
is 1.66 m concentration.
Which means that 1.66 moles of are present in 1 kg of the solvent, water.
Mass of water = 1 kg = 1000 g
Moles of = 1.66 moles
Molar mass of = 98.079 g/mol
The formula for the calculation of moles is shown below:
Thus,
Total mass = 1000 g + 162.81114 g = 1162.81114 g
Density = 1.104 g/mL
Volume of the solution = Mass / Density = 1162.81114 / 1.104 mL = 1053.27 mL = 1.05327 L
Considering:-
<u>Molarity = moles/ Volume of solution = 1.66 / 1.05327 M = 1.58 M
</u>
0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>
The number of moles of a substance can be calculated using the following expression:
PV = nRT
Where;
- p = pressure (atm)
- v = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
0.75 × 11.2 = n × 0.0821 × 300
8.4 = 24.63n
n = 8.4 ÷ 24.63
n = 0.34 moles
Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
Learn more about number of moles at: brainly.com/question/1190311
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