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tigry1 [53]
3 years ago
12

Question 4

Physics
1 answer:
anygoal [31]3 years ago
3 0

Answer:

The answer is 24 A ....using I = V/R

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Newly discovered planet has twice the mass and three times the radius of the earth. What is the free-fall acceleration at its su
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g_n=\dfrac{2}{9}g

Explanation:

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g_n=\dfrac{G2M}{(3R)^2}\\\Rightarrow g_n=\dfrac{2GM}{9R^2}

Dividing the two equations we get

\dfrac{g_n}{g}=\dfrac{\dfrac{2GM}{9R^2}}{\dfrac{GM}{R^2}}\\\Rightarrow \dfrac{g_n}{g}=\dfrac{2}{9}\\\Rightarrow g_n=\dfrac{2}{9}g

The acceleration due to gravity on the other planet is g_n=\dfrac{2}{9}g

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