The Correct answer to number 1 is A or D
The correct answer to number 2 is C because transmission meaning is to travel.
PS. I think number 1 is D
The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 ×
J/g per hour
<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>
- D + T → He + n
- The D-T fusion reaction results in a Helium (He) and neutron (n)
E = 17.59 MeV
Mass = 2.014u + 3.016u
= 5.030u
Energy per Kg = (17.59×
×1.6×
) ÷ ( 5.030×1.66×
)
= 3.37×
J/Kg
= 3.0×
J/g
Rate of fuel burning in grams per hour = 3.0×
× 3600
= 3.6×3.0×
= 1.08 ×
J/g per hour
To learn more about fusion reactor and energy production, refer
brainly.com/question/13399644
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Answer:
1.t=-1.96sec
2.H=4.8m
3.T=1.96sec
4.R=19.2m
Explanation:
u=9.8,t=?,sin theta=1
using formula t=2usintheta/g
t=2x9.8x1=19.6/10
t=1.96seconds
using formula H=u(squared)sin(squared)theta/2g
H=9.8(squared)x1(squared)/2x10
H=96x1/20
H=96/20
H=4.8m
using formula T=2usintheta/g
T=2x9.8x1/10
T=19.6/10
T=1.96sec
using the formula R=u(squared)sin2theta/g
R=9.8(squared)x2/10
R=96x2/10
R=192.08/10
R=19.2
Answer:
In a primary cell, two electrodes (one of copper and other of zinc) of metal atoms are used. These electrodes are dipped in an electrolyte solution that causes the metals to produce their respective positive and negative ions.
In this way, the flow of charges takes place and supply the electricity to the source.
Unlike a primary cell, a dry cell contains paste of an electrolyte instead of the solution. The contents of electrolyte paste react with each other through a chemical process and convert the chemical energy into electrical energy.
Answer:
(a) 2.5 cm
(b) Yes
Solution:
As per the question:
Mass of Uranium-235 ion, m = 
Mass of Uranium- 238, m' = 
Velocity, v = 
Magnetic field, B = 0.250 T
q = 3e
Now,
To calculate the path separation while traversing a semi-circle:

The radius of the ion in a magnetic field is given by:
R = 



Now,
By putting suitable values in the above eqn:


(b) Since the order of the distance is in cm, thus clearly this distance is sufficiently large enough in practical for the separation of the two uranium isotopes.