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Nitella [24]
3 years ago
9

A rock rolls down a hill. Which form of energy is this an example of? (2 points)

Physics
1 answer:
Bond [772]3 years ago
6 0

Answer:

c.Mechanical

Explanation:

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A uniform solid disk and a uniform hoop are placed side by side at the top of an incline of height h. If they are released from
svlad2 [7]

Answer:

) the uniform disk has a lower moment of inertia and arrives first.

Explanation:

(a) the uniform disk has a lower moment of inertia and arrives first.

(b) Let's say the disk has mass m and radius r, and

the hoop has mass M and radius R.

disk: initial E = PE = mgh

I = ½mr², so KE = ½mv² + ½Iω² = ½mv² + ½(½mr²)(v/r)² = (3/4)mv² = mgh

m cancels, leaving v² = 4gh / 3

hoop: initial E = Mgh

I = MR², so KE = ½MV² + ½(MR²)(V/R)² = MV² = Mgh

M cancels, leaving V² = gh

Vdisk = √(4gh/3) > Vhoop = √(gh)

3 0
3 years ago
Taste and smell are called chemical senses because:
Bingel [31]

Answer:

The answer is a," their receptors are sensitive to chemical molecules."

3 0
4 years ago
As the ambulance got closer, Marge noticed that the pitch of the siren got higher. This happened because
Neko [114]

Explanation :

As the ambulance got closer, Marge noticed that the pitch of the siren got higher. This is due to the Doppler's effect.

The siren of the ambulance has a higher pitch when it approaches Marge. When the waves move away from him, it will have a lower pitch.

As the waves come closer to us, the waves become compressed and hence the frequency of the wave increases.

5 0
3 years ago
Read 2 more answers
A bullet of .05 kg is fired into a block of wood. Knowing that the bullet left the gun with a muzzle velocity of 350. m/s, and t
Lunna [17]

We know, Impulse of a body is change in momentum.

Also, the final velocity of wood block is 0 m/s.

So, Impulse = Final Momentum - Initial Momentum

Impulse = 0 - ( 0.05 kg × 350 m/s )

Impulse = - 17.5 kg m/s

Therefore, the impulse exerted by the wood on the bullet is -17.5 kg m/s .

6 0
3 years ago
You place a piece of aluminum at 250.0∘C ∘ C in 9.00 kg k g of liquid water at 20.0∘C ∘ C . None of the water boils, and the fin
Mice21 [21]

Answer:

m₁ = 0.37 kg

Explanation:

According to Law of conservation of energy:

Heat Lost by Aluminum = Heat Gained by Water

m₁C₁ΔT₁ = m₂C₂ΔT₂

where,

m₁ = mass of piece of aluminum = ?

C₁ = specific heat capacity of aluminum = 900 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 250°C - 22°C = 228°C

m₂ = mass of water = 9 kg

C₂ = specific heat capacity of water = 4200 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 22°C - 20°C = 2°C

Therefore,

m₁(900 J/kg.°C)(228 °C) = (9 kg)(4200 J/kg.°C)(2°C)

m₁ = (75600 J)/(205200 J/kg)

<u>m₁ = 0.37 kg</u>

5 0
3 years ago
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