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1 year ago

A radio station broadcast on a frequency of 3.7 mhz what is the energy of the radio wave

1 answer:

3 0

A radio station broadcast on a frequency of 3.7 mhz what is the energy of the radio wave A radio station broadcasts its programmes at a wavelength of 500 m. Find the frequency of the radiowaves transmitted by the radio station, if the speed of radiowaves in air is 3 x 108 m/s. Ans: 6 x 10 Hz

<h3>What is radio station ?</h3>

Radio broadcasting is the act of sending audio (sound), occasionally together with accompanying metadata, across radio waves to radio receivers used by the general public. Unlike satellite radio, which uses a satellite in Earth's orbit, terrestrial radio broadcasting uses a land-based radio station to transmit radio waves. The listener needs a broadcast radio receiver to hear the material (radio). A radio network with which stations frequently have affiliations provide content in a standard radio format, whether through broadcast syndication, simulcasting, or both. Radio stations use a variety of modulations to transmit their signals, including FM (frequency modulation), which is an older analog audio standard, and AM (amplitude modulation).

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Glands that are responsible for lubricating the skin and minimizing water loss are called

weqwewe [10]

Answer:

your answer would be Sebaceous glands

Explanation:

these glands secrete oil/wax called sebum to lubricate and waterproof your skin. Hope this helps :)

3 0

3 years ago

As an electron approaches a proton, the electric force of attraction

Andreas93 [3]

I believe the answer is option B. As an electron goes near a proton, the force of attraction would increase. Electron is negatively charged while the proton is positively charged so they would naturally attract each other. Distance and force of attraction is inversely related so that as the distance decreases, the force increases.

4 0

3 years ago

Read 2 more answers

Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec

Alex

Answer:

ωM = 1.7 rad/s

vM = 3.4 m/s

ωA = 1.7 rad/s

vA = 1.7 m/s

Explanation:

Calculation of the angular speed (ω)

We use the following formula for circular motion:

ω = θ / t Formula (1)

Where:

ω: angular speed (rad/s)

θ:angle that the particle travels (rad)

t: time interval (s)

Equivalence

1 revolution = 2π rad

Data

θ= 1 revolution = 2π rad

t = 3.7 s

We replace data in the formula (1):

ω = (2π rad) / (3.7s )= 1.7 rad/s

Because the angular speed depends only on the number of turns in a time interval then Mary's angular speed (ωM) is equal to Alex's angular speed (ωA).

ωM = ωA = 1.7 rad/s

Calculation of the tangential speed (v)

We use the following formula for circular motion:

v = ω*r Formula (2)

Where:

v : tangential speed (m/s)

ω: angular speed ( rad/s)

r : radius of the circular path (m)

Data

ωM = ωM = ω= 1.7 rad/s

rM = 2m : Mary's circular path radius

rA = 1m : Alex's circular path radius

We apply the formula (2) to calculate v:

vM = ω* rM = (1.7) (2) = 3.4 m/s

vA = ω* rA = (1.7) (1) = 1.7 m/s

7 0

3 years ago

Which would require the greater energy; slowing down of the orbital speed of the Earth so it crashes into the sun, or speeding u

tresset_1 [31]

Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Explanation: To find the answer, we need to know more about the Orbital and escape velocities.

<h3>What is Orbital and Escape velocity?</h3>

Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.
The expression for orbital velocity near to the surface of earth will be,

$V_o=\sqrt{gR}$

Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.
The expression for orbital velocity will be,

$V_e=\sqrt{2gR}$

If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.
We need about twice the raw speed to go to the sun than to leave the sun.

Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Learn more about orbital and escape velocity here:

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3 0

1 year ago

A mover loads a crate onto a truck bed 1.6m from the street using a ramp that is 4.6m long. What is a mechanical advantage?

Ne4ueva [31]

Answer:

Mechanical advantage = 2.875

Explanation:

Given:

A diagram is shown below for the above scenario.

Length of ramp (Effort arm) = 4.6 m

Height of truck bed ( Resistance length) = 1.6 m

Mechanical advantage (MA) is the ratio of effort arm and resistance length.

So, mechanical advantage is given as,

$MA=\frac{\textrm{Effort arm}}{\textrm{Resistance length}}= \frac{4.6}{1.6}=2.875$

6 0

3 years ago