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kaheart [24]
3 years ago
9

Some Tiny College staff employees i s are information technology (IT) personnel. Some IT personnel provide technology support fo

r academic programs. Some IT personnel provide technology infrastructure s programs and technology infrastructure support. IT personnel are not professors. IT personne are required to take periodic training to retain their technical expertise. Tiny College tracks a IT personnel training by date, type, and results (completed vs. not completed). Given that information, create the complete ERD containing all primary keys, foreign keys, and main attributes.

Engineering
1 answer:
Westkost [7]3 years ago
3 0

Answer:

solution in the picture attached

Explanation:

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A resistor R = 1 kohm an inductor L = 1 mH and a capacitor C = 1 muFare used in a circuit which is driven by a voltage source v_
shusha [124]

Answer:

A = 10, B = -45

Explanation:

Given a voltage source of the form A\cos(\omega t + \phi) the correspondent phasor is of the form A\angle \phi. Note that the phasor form is only considered for sources expressed in a cosine form. IN this case, since the question is only asking for the phasor of the voltage form, the way the other devices are connected is neglected and do not affect the answer. Then, to get the phasor of the voltage source, we need to express it in a cosine form. To do so, the following trigonometric equation is used \sin(\omega t + \phi) = \cos (\omega t +\phi - 90^\circ)

Therefore, the voltage source, in terms of cosine, is equivalent to 10 \cos(10^5 t +45^\circ- 90^\circ)= 10 \cos(10^5 t -45 ^\circ ), so the correspondent phasor form is 10\angle -45.

5 0
4 years ago
Blank is an art form in which the focus is to make life and society better
Ganezh [65]

Engineering is an art form in which the focus is to make life and society better

4 0
2 years ago
A 3/8-16 UNC nut and bolt are used to assemble steel plates. The clearance holes in the plates are 7/16 in. The plates are clamp
steposvetlana [31]

Answer:

a) T=41.25 in-lb

b) Resulting stress=6493.5 lb/in^2

Explanation:

a) The torque is:

T=C*D*F

where C is the torque coefficient, F the force and D is 3/8. Replacing:

T=0.22*3/8*500=41.25 in-lb

b) The area is:

A=0.25\pi (D-\frac{0.9743}{n})^{2}=0.25\pi   (3/8-\frac{0.9743}{16})^{2}=0.077 in^{2}

The resulting stress is:

Resulting stress=\frac{F}{A}=\frac{500}{0.077} =6493.5 lb/in^{2}

8 0
3 years ago
a) Complete the following methods description using the correct tense for the verb in brackets. (This student is using passive v
ExtremeBDS [4]

Answer:

Each of the metal specimens HAS an indentation near the center to ensure that the fracture point would occur in this region. Tension tests WERE CONDUCTED as follows. Two pieces of reflective tape WERE PLACED approximately 1 inch apart in the center of the specimen where the indentation 4 WAS LOCATED. The width and the thickness of the specimen at this location WAS MEASURED using a Vernier caliper. Then the specimen WAS SECURED in the MTS Load Frame. A laser extensometer WAS PLACED into position to measure the deformation of the specimen. The laser extensometer WAS USED to measure the original distance between the pieces of reflective tape. The MTS WAS SET to elongate the specimen one tenth of an inch every minute.

5 0
3 years ago
What is
Yuri [45]

Answer:

1

Explanation:

because every time you dived a number by its own number it is 1

6 0
2 years ago
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