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3 years ago

The shear force diagram is always the slope of the bending moment diagram. a)True b)- False

Engineering

1 answer:

lara [203]3 years ago

8 0

Answer:

True

Explanation:

Shear force diagram is a diagram which is drawn by calculating the shear force either to the right of the section or to the left of the section .

shear force is also be define as the change of moment w.r.t to distance

V= $\frac{\mathrm{d}M }{\mathrm{d} x}$

where V is shear force and M is bending moment.

from the equation we can clearly say that shear force diagram is slope of bending moment diagram.

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A homogeneous 800kg bar AB is supported at either end by a cable asshown in the figure

aleksandr82 [10.1K]

The smallest area of each cable if the stress is not to exceed 90MPa in bronze is 43.6 mm² and 120MPa in steel is 32.7 mm².

<h3>What is normal stress?</h3>

If the direction of deformation force is perpendicular to the cross-sectional area of the body, the stress is called normal stress. Changes in wire length and body volume will be normal.

σ = P/A

Where, σ = Normal stress

P = Pressure

A = Area

1 Kg = 9.81 N

800 kg = 7848 N

Since the rod is half bronze and half steel

800 kg = 7848/2

= 3924 N

Pₙ = Fₙ = 3924 N [n = Bronze]

Pₓ = 3924 N [x = steel]

Given,

σₙ = 90MPa

σₓ = 120MPa

Aₙ = ?

Aₓ = ?

Aₙ = Pₙ/σₙ

Aₙ = 3924/90

Aₙ = 43.6 mm²

Aₓ = Pₓ/σₓ

Aₓ = 3924/120

Aₓ = 32.7 mm²

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1 year ago

A ladder logic program and the associated physical input/output components are given below. Lighting changes from full darkness

Katena32 [7]

Answer:

O2 is true.

Explanation:

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3 years ago

The top surface of an L = 5mmthick anodized aluminum plate is irradiated with G = 1000 W/m2 while being simultaneously exposed

puteri [66]

Answer:

$J=1963W/m^2$

$q_{rad}=963w/m^2$

$\triangle T= -0.378k/s$

Explanation:

From the question we are told that:

$L=5mm => 5*10^{-3}\\Irradiation G=1000W/m^2\\h=50W/m^2\\T_{infinity} = 25C.\\Plate\ temperature\ T_p= 400 K\\\alpha=0.14\\E=0.76$

at Temp=400K

$E=2702kg/m^2,c=949J/kgk$

Generally the equation for Radiosity is mathematically given by

$J=eG+\in E_p$

$J=(1-\alpha)G+\in \sigma T^4$

$J=(1-0.14)1000+0.76 (5.67*10^_{8}) (400)^4$

$J=1963W/m^2$

Generally the equation for net radiation heat flux $q_{rad}$ is mathematically given by

$q_{rad}=J-G\\q_{rad}=1963-1000$

$q_{rad}=963w/m^2$

Generally the equation for and the rate of plate temp $\triangleT$ is mathematically given by

$\triangle T= -\frac{q_{con} +q_{rad}}{Ecl}$

$\triangle T= \frac{45(400)-(30+273+963)}{(2702*949*0.005)}$

$\triangle T= -0.378k/s$

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3 years ago

Complete the given statement with the most appropriate word.

siniylev [52]

Answer:

A. approachable

Explanation:

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Which dimensionless parameter tells whether flow disturbances will be attenuated or amplified? a. Pr b. Re C G d. St e. Fe

Aleonysh [2.5K]

Answer:

b. Re

Explanation:

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3 years ago