Which graph represents the equation below? 7x – 2y = -10
1 answer:
You might be interested in
the picture in the attached figure
Step 1
Find the perimeter of the scaled-down model of a walkway (Quadrilateral ABCD)
Step 2
Find the scale factor
if Quadrilateral ABCD is similar to Quadrilateral EFGH
then
Step 3
Find the perimeter of the actual walkway (Quadrilateral EFGH)
therefore
the answer is
Answer:
D. linear; y = – 3x –6
Step-by-step explanation:
Answer:
Option (2).
Step-by-step explanation:
From the figure attached,
Since there is a common difference in each successive term and previous term of y,
y_{2}-y_{1}=-9-(-6)
= -3
y_{3}-y_{2}=-12-(-9)
= -3
Therefore, this data represents a linear equation.
Now we choose two points from the table given.
Let the points are (0, -6) and (1, -9)
Slope of this line 'm' = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}
m = \frac{-9+6}{1-0} = -3
Y-intercept 'b' = -6
Equation of the line will be,
y = -3x - 6
Option (2) will be the answer.
Answer: The correct answer is c
Step-by-step explanation: you would have to plot your graph and the put the answer in slop intercept for y=mx+b or y=-3x-6
Answer:
exponential; y = –6 • 1.5x
Step-by-step explanation:
1.5 x 1 = 1.5
1.5x-6= -9
There are two inequality equations to be graphed:
<span>x + y ≥ 4
2x + 3y < 12
For the first step, let's disregard the inequality symbols and take it like any conventional algebraic equation. This is to be able to graph the lines on a Cartesian planes first.
For the first equation, x+y=4. To find the x- and y-intercepts, let the other variable be 0. For example,
x-intercept:
x+0=4
x=4
y-intercept:
0+y=4
y=4
Therefore, you can graph the equation line by plotting the intercepts (4,0) and (0,4) and connecting them together. The same thing is done to the second equation:
x-intercept:
</span>2x + 0 = 12
x=12/2=6
y-intercept:
0 + 3y =12
y= 12/3 = 4
Therefore, you can graph the equation line by plotting the intercepts (6,0) and (0,4) and connecting them together. The graph is shown in the left side of the picture.
The next step would be testing the inequalities. Let's choose a point that does not coincide with the lines. That point could be (-5,-1).
x + y ≥ 4
-5 + -1 ≥4
-6 ≥ 4 --> this is not true. Thus, the solution of the graph must not include the area of this point. It includes everything to the right of the line denoted by the blue-shaded region.
2x + 3y < 12
2(-5) + 3(-1) <12
-13 < 12 ---> this is true. Thus, the solution would include this point. That includes all points to the left of the orange line denoted by the orange-shaded the region.
The region where blue and orange overlap is the solution of the system of equations, denoted by the green-shaded region.
<span>x + y ≥ 4
2x + 3y < 12
For the first step, let's disregard the inequality symbols and take it like any conventional algebraic equation. This is to be able to graph the lines on a Cartesian planes first.
For the first equation, x+y=4. To find the x- and y-intercepts, let the other variable be 0. For example,
x-intercept:
x+0=4
x=4
y-intercept:
0+y=4
y=4
Therefore, you can graph the equation line by plotting the intercepts (4,0) and (0,4) and connecting them together. The same thing is done to the second equation:
x-intercept:
</span>2x + 0 = 12
x=12/2=6
y-intercept:
0 + 3y =12
y= 12/3 = 4
Therefore, you can graph the equation line by plotting the intercepts (6,0) and (0,4) and connecting them together. The graph is shown in the left side of the picture.
The next step would be testing the inequalities. Let's choose a point that does not coincide with the lines. That point could be (-5,-1).
x + y ≥ 4
-5 + -1 ≥4
-6 ≥ 4 --> this is not true. Thus, the solution of the graph must not include the area of this point. It includes everything to the right of the line denoted by the blue-shaded region.
2x + 3y < 12
2(-5) + 3(-1) <12
-13 < 12 ---> this is true. Thus, the solution would include this point. That includes all points to the left of the orange line denoted by the orange-shaded the region.
The region where blue and orange overlap is the solution of the system of equations, denoted by the green-shaded region.