Answer:
The answer to your question is: yield = 56.27%
Explanation:
Data
CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br
18.54 ml 1-butanol 15.65 g of 1-bromobutane
% yield = ?
density = 0.81 g/ml
MM = 74 g 1- butanol
MM = 137 g 1-bromobutane
Process
Calculate mass of 1- butanol
density = mass/volume
mass = density x volume
mass = 0.81 x 18.54
mass = 15.02 g of 1-butanol
Theoretical yield
74 g of 1- butanol ----------------- 137 g of 1-bromobutane
15.02 g of 1- butanol ------------- x
x = (15.02 x 137) / 74
x = 27.81 g of 1-bromobutane
% yield = experimental yield / theoretical yield x 100
% yield = 15.65 / 27.81 x 100
% yield = 56.28
Answer:
Explanation:
2.2 pounds = 1 kg
495 pounds = x
2.2/495 = 1/x Cross multiply
2.2*x = 495 * 1 Divide by 2.2
2.2x/2.2 = 495/2.2
x = 225 kg
Answer:
-1
Explanation:
Many of the common polyatomicions have an electrical charge of.
Answer:
Option C (a higher; the same) is the appropriate response.
Explanation:
Given:
Temperature,
T = 300 K (both 
and 
)
As we know,
Average speed of a molecule,
⇒ 
Thus, the average speed of will be lower as its molar mass is greater than .
Now,
⇒ 
(not depend on molar mass)
Hence, it will be the same.
The other three alternatives aren't connected to the scenario given. So the above is the correct answer.
