<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
The balanced equilibrium reaction for the ionization of calcium fluoride follows:
s 2s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ca^{2+}][F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2)
We are given:
Putting values in above equation, we get:
To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:
Molar mass of calcium fluoride = 78 g/mol
Multiplying the solubility product, we get:
Hence, the correct answer is Option b.
A. Mass of the unknown gas.
The mass of the unknown gas is calculated by subtracting the weight of the empty flask from the mass when there was air in it.
m = 126.593 g - 125.623 g
Simplifying,
m = 0.97 grams
b. Molar mass of the gas
The molar mass of the gas is calculated by the ideal gas law.
PV = (m/M)RT
where P is pressure,V is volume, m is the mass, M is the molar mass, R is the universal gas constant, and T is temperature. Substituting the known values to the equation,
(733 mmHg/760 mmHg/atm)(0.20 L) = (0.97 g/M)(0.0821 L.atm/molK)(99 + 273.15 K)
The value of M in the equation is 153.64 g/mol.
<em>Answer: 153.64 g/mol</em>
Answer: 1.14 M
Explanation:
500 mL is equal to 0.5 L.
So, the molarity is (0.570)/(0.5) = 1.14 M
Answer:
ATOMIC MASS = Protons + Neutrons
34+43 = 77
Atomic Mass is 77
BRAINLIEST PLEASE
