<span>XY4Z2-->Square planar (Electron domain geometry: Octahedral) sp3d2
XY4Z-->Seesaw (Electron domain geometry: Trigonal bipyramidal) sp3d
XY5Z-->Square pyramidal (Electron domain geometry: Octahedral) sp3d2
XY2Z3-->Linear (Electron domain geometry: Trigonal bipyramidal) sp3d
XY2Z-->Bent (Electron domain geometry: Trigonal planar) sp2
XY3Z-->Trigonal pyramidal (Electron domain geometry: Tetrahedral) sp3
XY2Z2-->Linear (Electron domain geometry: Tetrahedral) sp3
XY3Z2-->T shaped (Electron domain geometry: Trigonal bipryamidal) sp3d
XY2-->Linear (Electron domain geometry: Linear) sp
XY3 Trigonal planar (Electron geometry: Trigonal planar) sp2
XY4-->Tetrahedral (Electron domain geometry: tetrahedral) sp3
XY5-->Trigonal bipyramidal (Electron domain geometry: Trigonal bipyramidal) sp3d
XY6-->Octahedral (Electron domain geometry: Octahedral) sp3d2</span>
The amount of energy that was used to heat Cu is 27.6 cal
<u><em>calculation</em></u>
Heat (Q) = M ( mass) x c(specific heat capacity) x ΔT( change in temperature)
where;
Q=?
M = 5.0 g
C=0.092 cal/g°C
ΔT = 80°c-20°c=60°C
Q is therefore = 5.0 g x 0.092 cal / g°c x 60°c =27.6 cal
The first two ionization energy of nickel are expressed as:
Ni(g) = Ni^+(g) + e^- Ni^+(g) = Ni^2+(g) + e^-
IOnization energy os the energy that is neccessary in order to remove one mole of electrons from an atom.
Hope this helps.
Answer:
Explanation:
Using Laplace's law of surface tension:
where:
P = pressure
T = surface tension
r = radius
In the longer alveoli with radius of 0.07 mm = 
; we have:
P = 
P = 
In the smaller alveoli with radius 0.05 mm = 
; we have:
P = 
P = 
The pressure difference can now be calculate as follows:
Pressure difference = 
Pressure difference =
