Question

What is the heat capacity of crystalline calcium carbide at 49.0°C?

Answer 1

Explanation:

Formula to calculate heat capacity is as follows.

               $C_{p}$ = a + bT + $cT^{-2}$

where, a, b and c are constants.

Their values at $49.0^{o}C$ are as follows.

     a = $68.62 \times 10^{-3}$        

     b = $1.19 \times 10^{-5}$

     c = $-8.66 \times 10^{10} \times 10^{-8}$

Hence, putting the given values into the above formula as follows.

               $C_{p}$ = a + bT + $cT^{-2}$

    = $68.62 \times 10^{-3} + 1.19 \times 10^{-5} \times 49.0 + -8.66 \times 10^{10} \times 10^{-8} \times (49.0)^{-2}$ kJ/mol K    

                             = 14.43 kJ/mol K

Thus, we can conclude that the heat capacity of crystalline calcium carbide at 49.0$^{o}C$ is 14.43 kJ/mol K.