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Bad White [126]
3 years ago
10

What are some common characteristics that infectious agents like viruses bacteria fungi and parasites have in common and what ar

e some differences
Physics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer: Some can and can not kill you

Explanation:

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Use the law of universal gravitation to describe the relationship between you and your desk
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The law of gravitation states that things closer to the core of gravitation, have a larger force pulling down on them. In relation of you to your desk, you and the desk are both drawn downwards towards the center of gravity.
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4 years ago
Which of the following describes the mass of an object precisely ? *
timurjin [86]

Answer:

2.345 would be the most precious because you have more numbers to work with and exact numbers

8 0
3 years ago
An object possesses both potential (PE) and kinetic (KE) energy. The object’s total mechanical energy is
Nina [5.8K]

Answer: PE+KE

Explanation:

5 0
3 years ago
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A clown at a birthday party has brought along a helium cylinder, with which he intends to fill balloons. When full, each balloon
Furkat [3]

Answer:

11

Explanation:

According to Boyle's law:

P\times V=constant

Thus,

P_{cylinder}\times V_{cylinder}=n\times P_{balloon}\times V_{balloon}

Where, n is the number of the balloons

From the question, it is given that:

For balloon:

P = 1.2\times 10^5 Pa

V = 0.040 m³

For cylinder:

P = 1.80\times 10^7 Pa

V = 0.0031 m³

So,

1.80\times 10^7\times 0.0031=n\times 1.2\times 10^5\times 0.040

n = 11.625

<u>So, Maximum number of balloons = 11</u>

7 0
3 years ago
The experimental apparatus shown in the figure above contains a pendulum consisting of a 0.66 kg ball attached to a string of le
lara31 [8.8K]

The problem is solved and the questions are answered below.

Explanation:

a. To calculate the speed of the 0.66 kg ball just before the collision

V₀ + K₀ = V₁ + K₁

= mgh₀ = 1/2 mv₁²

where, h= r - r cosθ

V = \sqrt{2gh}

 V = 2.42 m/s

b. Calculate the speed of the 0.22 kg ball immediately after the collision

y = y₀ + Vy₀t - 1/2 gt²

0 = 1.2 - 1/2 gt²

t = 0.495 s

x = x₀ + Vx₀t

1.4 = 0 + vx₀ (0.495)

Vx₀ = 2.83 m/s

C. To Calculate the speed of the 0.66 kg ball immediately after the collision

m₁ v₁ = m₁ v₃ + m₂ v₄

(0.66)(2.42) = (0.66) v₃ + (0.22)(2.83)

V₃ = 1.48 m/s

D. To Indicate the direction of motion of the 0.66 kg ball immediately after the collision is to the right.

E. To Calculate the height to which the 0.66 kg ball rises after the collision

V₀ + k₀ = V₁ + k₁

1/2 mv₀² = mgh₁

h₁ = v₀²/2 g

  = 0.112 m

F. Based on your data, No the collision is not elastic.

Δk = 1/2 m₁v₃² =1/2 m₂v₄² - 1/2 m₁v₁²

     = 1/2 (0.66)(1.48)² + 1/2 (0.22)(2.83)² - 1/2 (0.66)(2.42)²

    = - 0.329 J

Hence, kinetic energy is not conserved.

8 0
3 years ago
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