I had this question before can you show me the answer choices
Answer:
12 kg
Explanation:
Momentum before collision = momentum after collision
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
After the collision, they have the same velocity, so v₁ = v₂ = v:
m₁ u₁ + m₂ u₂ = m₁ v + m₂ v
m₁ u₁ + m₂ u₂ = (m₁ + m₂) v
We know that m₁ = 6 kg, u₂ = 0 m/s, and v = u₁ / 3.
(6 kg) u₁ + m₂ (0 m/s) = (6 kg + m₂) (u₁ / 3)
(6 kg) u₁ = (6 kg + m₂) (u₁ / 3)
6 kg = (6 kg + m₂) (1/3)
18 kg = 6 kg + m₂
m₂ = 12 kg
The freezing point is the same as the melting point.
If it freezes at -58°C, hence the melting point is also <span>-58°C.</span>
Answer:
The minimum angular speed 57.0 rad/s
Explanation:
In this exercise we must use the relationships between the angular and linear magnitudes, for the speeds we have
v = w r
As they give us that linear velocity is constant, we will calculate the angular velocity for the two radii, external and internal
r1 = 11.75 cm (1 m / 100cm) = 0.1175 m
w1 = v / r1
w1 = 6.70 / 0.1175
w1 = 57.0 rd / s
R2 = 4.50 cm = 0.0450 m
w2 = 6.70 / 0.0450
w2 = 148 rad / s
The minimum angular speed 57.0 rad / s
Jxhdiebdnsskoshdhrjrbdksusvsjsowiw