Question

Onur drops a basketball from a height of 10\,\text{m}10m10, start text, m, end text on Mars, where the acceleration due to gravity has a magnitude of 3.7\,\dfrac{\text{m}}{\text{s}^2}3.7 s 2 m ​ 3, point, 7, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. We want to know how many seconds the basketball is in the air before it hits the ground. We can ignore air resistance.

Answer 1

Answer:

Explanation:

Given that,

Basket ball is drop from height

H=10m

It is dropped on planet mass

And the acceleration due to gravity on Mars is given as

g= 3.7m/s²

Time taken for the ball to reach the ground

Initial velocity of the body is zero

u=0m/s

Using equation of motion: free fall

H = ut + ½gt²

10 = 0•t + ½ × 3.7 ×t²

10 = 0 + 1.85t²

10 = 1.85t²

Then, t² =10/1.85

t² = 5.405

t = √ 5.405

t = 2.325seconds

So the time the ball spend on the air before reaching the ground is 2.325 seconds