Newton said . . . F = m a
Divide each side by m . . . a = F / m
Acceleration = (force) / (mass)
Acceleration = (145.O N) / (40.0 kg)
<em>Acceleration = 3.625 m/s²</em>
The electron charge is called the Elementary Charge, given by:
The Eletrostatic Force bewteen two changes is giver by Coulomb Law:
Substituing the unknowns, we have:
If you notice any mistake in my english, please let me know, because i am not native.
Complete question
A student measures the mass of a 1.0 kg standard bar. He obtains measurements of 0.77 kg, 0.78 kg, and 0.79 kg. Which describes his measurements
a)precise but not accurate
b)accurate but not precise
c)neither precise nor accurate
d)both precise and accurate
Answer:
The measurement is precise but not accurate
Explanation:
A measurement can either be precise or accurate.
- A Precise measurement describes how close the measured values are to each other.
- An accurate measurement describes how close a measured value is to the true value.
In this question, the measured values (0.77 kg, 0.78 kg and 0.79 kg) are far from the true value (1.0 kg), therefore the measurement is not accurate.
However, the measured values (0.77 kg, 0.78 kg and 0.79 kg) are close to each other, therefore the measurement is precise.
Therefore the correct option is 'a' the measurement is precise but not accurate
Answer: 0 m/s
Explanation: The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.
We know that, the slope of a position-time graph gives velocity of an object. It can be given by :
In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.
It means its velocity is equal to at this time or we can say that ladybug is at rest.