Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.

Note that
1 m = 1609.34 m.
Therefore
v = (60 mi/h)*(1609.34 m/mi)*(1/3600 h/s) = 26.822 m/s
Use the formula
v = u + at
(26.822 m/s) = (2.35 m/s²)*(t s)
t = 26.822/2.35 = 11.4 s

Answer: 11.4 s

Part b.
We already determined that v = 60 mi/h = 26.822 m/s.
t = 0.6 s
Therefore
(26.822 m/s) = (a m/s²)*(0.6 s)
a = 26.822/0.6 = 44.7 m/s²

Answer: 44.7 m/s²

6 0

2 years ago

Label the diagram Please

Nitella [24]

The earth tilt about 23 degrees which leads to the formation of seasons on earth.

<h3>At what degree the earth tilt?</h3>

This is tilted at 23 degrees from the vertical. The northern hemisphere is in the winter season.

This is the path as the earth revolves around the sun. It takes 1 year to complete this path.

This is the path as the earth rotates around its.

So we can conclude that the earth tilt about 23 degrees which leads to the formation of seasons on earth.

Learn more about season here: brainly.com/question/25870256

#SPJ1

8 0

2 years ago

The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 10−31 kg from rest to 3 × 107 m/s within

zaharov [31]

Answer:

Electric field, E = 40608.75 N/C

Explanation:

It is given that,

Mass of electrons, $m=9.1\times 10^{-31}\ kg$

Initial speed of electron, u = 0

Final speed of electrons, $v=3\times 10^7\ m/s$

Distance traveled, s = 6.3 cm = 0.063 m

Firstly, we will find the acceleration of the electron using third equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{(3\times 10^7)^2}{2\times 0.063}$

$a=7.14\times 10^{15}\ m/s^2$

Now we will find the electric field required in the tube as :

$ma=qE$

$E=\dfrac{ma}{q}$

$E=\dfrac{9.1\times 10^{-31}\times 7.14\times 10^{15}}{1.6\times 10^{-19}}$

E = 40608.75 N/C

So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.

3 0

2 years ago

If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be

galben [10]

Answer: If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be directed OUTWARD. Thus, the equilibrium potential for this ion would be POSITIVELY charged. The correct answer is OUTWARD: POSITIVELY.

Explanation: Usually across a cell membrane there is a force that acts on it which is as a result of unequal distribution of charges. This force is known as electrochemical driving force. It is determined by the difference between the membrane potential ( that is, the electrical potential difference across the cell membrane) and the ion equilibrium potential. The membrane potential of a cell helps in signal transmission between different parts of the cell and results when there is unequal distribution across the cell.

Therefore If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be directed outward.Thus, the equilibrium potential for this ion would be positively charged.

8 0

2 years ago

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