Answer:
External users will be able to access the message.
Explanation:
When dealing with the internal email system of an enterprise, it's possible to do a recall on the message. If someone on the internal list didn't open the message yet, it will simply be deleted from his queue and it will appear as is that email never existed.
For external users, once the email has been sent, it cannot be recalled... so they'll be able to access it no matter what, because that email exists on an external server on which you have no management control.
Answer: False
Explanation:
This means that the mappings between the two schemas may be specified in either one of these languages.In most relational DBMSs today, there is no specific language that performs the role of SDL. Instead, the internal schema is specified by a combination of functions, parameters, and specifications related to storage. These permit the DBA staff to control indexing choices and mapping of data to storage
The silver market dropped sharply in <span>1898,</span> hurting Bolivia's income.
The entire mining business was in decline as a result of destruction, flooding, and abandonment of mines. Lack of investment and insufficiency of labor contributed to a pointy drop by silver production. Agricultural production was low, and Bolivia had to import food, even the essential staples consumed by the Indian population. the government had serious money difficulties as a result of the massive military expenditures and debt payments to the Republic of Peru as compensation for the military of liberation. of these issues were aggravated by the isolation of the new republic from the skin world and therefore the difficulties of securing its borders.
Answer:
Check the explanation
Explanation:
Going by the question above,there are 2 routers in a sequence amid Host A and Host B and using store-and-forward routing.
So that time would conprise of both propagation delay and transmission time
Propagation delay is nothing but the time taken for traveling.
Transmission delay is the amount of delay time from the beginning to end of transmission)
Now,
Propagation delay = distance traveled / speed of propagation
= 161200 / 2.7 *108 = 59703703.70 * 10-8 mili sec
Transmission delay:
= packet size / bandwidth
= 4 / (9.1 * 1024) = 4.2925 * 10-1 mili sec
Let us assume routers have zero (0) processing time
total time = Transmission delay by host A + Transmssion delay by router1 + Transmssion delay by router2 + propagation time
= 3 * ( 4.2925 * 10-1 ) + (59703703.70 * 10-8)
= 1.28775 + 0.5970370370 ms
= 1.884787 ms
Answer:
TRUE
Explanation:
In telecommunication and computing, there are different units of data storage. The most commonly used units are the bit and the byte.
A bit is the capacity of the system having only two states.
Whereas, the byte, also known as octet, is equal to eight bits. The unit symbol for Byte is B. In many computers, it is the smallest addressable unit of memory.
Therefore, <u>the given statement is TRUE</u>.
