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dezoksy [38]
3 years ago
10

What is a chemical equation for the second ionization for lithium

Chemistry
1 answer:
Orlov [11]3 years ago
5 0
The 2nd ionization energy is removing a 2nd electron from that resulting cation: 
<span>Li+ --> Li2+ + 1e- </span>
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A scientist measures out equal volumes and concentrations of hydrochloric acid and sodium hydroxide solutions. When mixed, these
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Neutral solution is formed.

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If the sample has a total mass of 5.76 g and contains 1.79 g k, what are the percentages of kbr and ki in the sample by mass
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The percentages of KBr and KI  in the sample by mass is 80.68 and 19.32 % respectively.

<h3>What is Molar Mass ?</h3>

Molar mass is defined as the mass contained in 1 mole of sample.

It is given that

the sample has a total mass of 5.76 g contains KBr and KI

and contains 1.79 gm of K is present

what is the percentage of KBr and KI in the sample

Molecular weight of K = 39

Molecular weight of Br = 79.9

Molecular weight of I = 126.9

In KBr the mass percentage of K is 39/(39+79.9) = 32.89%

In KI the mass percentage of K is 39/(39+126.9) = 23.5%

Let the mass of KBr present in the sample is x

K will be 0.3289 x

and let the mass of KI present be y

K will be 0.235y

x +y =5.76

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0.0939y = 0.1045

y = 1.1125 gm

x = 5.76-1.1125

x = 4.6475 gm

% of KBr = (4.6475/5.76  )*100 = 80.68 %

% of KI = (1.1125/5.76) *100 = 19.32%

To know more about Molar Mass

brainly.com/question/12127540

#SPJ1

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