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EleoNora [17]
11 months ago
9

An oxidation-reduction reaction that is also a synthesis reaction

Chemistry
1 answer:
Aleonysh [2.5K]11 months ago
7 0

The example of a chemical combination that can also be said to be a synthesis reaction is; 2Mg(s) +O_{2} (g) -- > 2 MgO(s)

<h3>What is a synthesis reaction?</h3>

We know that the meaning of the synthesis reaction is quite central as we attempt to answer the question that is lying right before us here. If we are talking about the synthesis reaction then our mind must have to go to the kind of reaction in which there is the combination of two or more so as to produce a single compound.

As we are talking about the synthesis reaction, we would have to look at the reaction that would give rise to a single product as it has been written. Let us also recall that we have been told that the reaction is a  oxidation-reduction reaction thus there is a change in oxidation number in the process of the reaction as shown.

Learn more about synthesis reaction:brainly.com/question/16987748

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What is the molar mass of glucose, C3H603?
ziro4ka [17]

Answer:

The mass percentage of carbon can be found easily using the molar mass of C6H12O6, 180.1559 g/mol. We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass. C6H12O6 = CO2 + C3H6O3 + CH3OCH3 Take fructose for example. Compound.

Explanation: I looked it up

4 0
2 years ago
The equation of 3times x is 38​
MrMuchimi

Answer is 38/3 or 12.67

3x=38

x=38/3

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4 0
2 years ago
Explain how a water strider can float on the surface of water without sinking.
Rainbow [258]

Answer:

low weight and great area

Explanation:

8 0
3 years ago
calculate atomic weight of silver which has two isotopes with the following properties : silver-107 (106.91 amu, 51.84% natural
Julli [10]

Answer: The atomic weight of silver is 107.87 amu

Explanation:

Mass of isotope silver-107  = 106.91 amu

% abundance of isotope silver -107 = 51.84% = \frac{51.84}{100}=0.5184

Mass of isotope silver-109 = 108.90 amu

% abundance of isotope silver-109  = 48.16% = \frac{48.16}{100}=0.4816

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(106.91\times 0.5184)+(108.90\times 0.4816)]

A=107.87amu

Thus atomic weight of silver is 107.87 amu

8 0
3 years ago
Calculate the amount, in moles, of each of the following. You may round atomic masses to one decimal place.
Vlada [557]

Answer:

The answer to your question is:

a) 0.023 mol of CdS

b) 0.12 mol of MoO3

c) 7.3 mol of AlPO4

Explanation:

a) CdS

MW = 112.4 + 32

      = 144 g

                                144g ------------------ 1 mol

                                  3.28g --------------  x

                                 x = (3.28 x 1) / 144

                                 x = 0.023 mol

b) MoO3

MW = 96 + 3(16) = 144 g

                              144g -------------------  1 mol

                               17.5g -----------------   x

                               x = (17.5 x 1) / 144

                               x = 0.12 mol

c) AlPO4

MW = 27 + 31 + 4(16)

MW = 122 g

                            122 g ------------------  1mol

                            890 g ------------------   x

                            x = (890 x 1) / 122

                            x = 7.3 mol of AlPO4

7 0
3 years ago
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