Answer:
The mass percentage of carbon can be found easily using the molar mass of C6H12O6, 180.1559 g/mol. We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass. C6H12O6 = CO2 + C3H6O3 + CH3OCH3 Take fructose for example. Compound.
Explanation: I looked it up
Answer is 38/3 or 12.67
3x=38
x=38/3
therefore answer is the one mentioned above
Answer:
low weight and great area
Explanation:
Answer: The atomic weight of silver is 107.87 amu
Explanation:
Mass of isotope silver-107 = 106.91 amu
% abundance of isotope silver -107 = 51.84% = 
Mass of isotope silver-109 = 108.90 amu
% abundance of isotope silver-109 = 48.16% = 
Formula used for average atomic mass of an element :

![A=\sum[(106.91\times 0.5184)+(108.90\times 0.4816)]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%28106.91%5Ctimes%200.5184%29%2B%28108.90%5Ctimes%200.4816%29%5D)

Thus atomic weight of silver is 107.87 amu
Answer:
The answer to your question is:
a) 0.023 mol of CdS
b) 0.12 mol of MoO3
c) 7.3 mol of AlPO4
Explanation:
a) CdS
MW = 112.4 + 32
= 144 g
144g ------------------ 1 mol
3.28g -------------- x
x = (3.28 x 1) / 144
x = 0.023 mol
b) MoO3
MW = 96 + 3(16) = 144 g
144g ------------------- 1 mol
17.5g ----------------- x
x = (17.5 x 1) / 144
x = 0.12 mol
c) AlPO4
MW = 27 + 31 + 4(16)
MW = 122 g
122 g ------------------ 1mol
890 g ------------------ x
x = (890 x 1) / 122
x = 7.3 mol of AlPO4