Answer:
6,226 tiles of 9 in are needed to cover an area of 400 square feet
Step-by-step explanation:
Let
A -----> an area in square feet
t(A) ---> the total number of 9 in. tiles needed
we have
For A=400 ft^2
substitute in the equation and solve for t
That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet
Answer:
3
Step-by-step explanation:
3x+3-x+3=12
3x-x=12-3-3
2x=6
x=6/2
x=3
68
I hope you understand this
Well subtract 8 from 1000 and then do that five times. so 992,984,976,968, and 960<span />
Answer:
<u><em>note:</em></u>
<u><em>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</em></u>
