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Ksivusya [100]
3 years ago
9

To move a suitcase up to the check-in stand at the airport a student pushes with a horizontal force through a distance of 0.95 m

. If the work done by the student is 32 J, what is the magnitude of the force he exerts?
Physics
1 answer:
hoa [83]3 years ago
3 0

Answer:

33.68 N

Explanation:

Data

W= 32J

d- 0.95m

F= ?

W=Fd

They are asking for the magnitude which is the force, so you need to solve for force.

F=W/d

= 32J/ 0.95m

= 33.68 N

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you almost made me drop my croissant

Explanation:

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A billiard ball with a mass of 1.5kg is moving at 25m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find
aliya0001 [1]

Answer:

The velocity of the second ball after the collision will be 16.3 m/s.

Step-by-Step Explanation:

Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.

Let: mass of the first ball = m1 = 1.5 kg

mass of the second ball = m2 =  2.3 kg

Momentum before the collision:

velocity of the first ball = v1 = 25 m/s

velocity of the second ball = v2 = 0 m/s

[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]

Momentum after the collision:

velocity of the first ball = v1 = 0 m/s

velocity of the second ball = v2 = x

[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]

According to law of conservation of momentum:

Initial momentum = Momentum after collision

37.5 = 2.3*x

⇒ x = 37.5/2.3

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4 0
3 years ago
A wave pulse travels along a string at a speed of 230 cm/s . Note that parts a - d are independent and refer to changes made to
Oksanka [162]

a) The speed of the wave will increase by a factor \sqrt{2}.

b) The speed of the wave will halve

c) The speed of the wave will double

Explanation:

a)

The speed of a standing wave on a string is given by

v=\sqrt{\frac{T}{m/L}}

where

T is the tension in the string

m is the mass of the string

L is the length of the string

In this part of the problem, the tension in the string is doubled, so that the new tension is

T' = 2T

Substituting into the equation, we find the new speed of the wave in the string:

v'=\sqrt{\frac{T'}{m/L}}=\sqrt{\frac{2T}{m/L}}=\sqrt{2}\sqrt{\frac{T}{m/L}}=\sqrt{2}v

So, the speed will increase by a factor \sqrt{2}.

b)

We can solve also this part by referring to the formula

v=\sqrt{\frac{T}{m/L}}

where

T is the tension

m is the mass

L is the length

In this case, the string mass is quadrupled, so the new mass is:

m' = 4m

Substituting into the equation, we find what happens to the speed of the wave:

v'=\sqrt{\frac{T}{m'/L}}=\sqrt{\frac{T}{4m/L}}=\frac{1}{\sqrt{4}}\sqrt{\frac{T}{m/L}}=\frac{1}{2}v

So, the speed of the wave will halve.

c)

Again, we can solve this part by referring to the same equation

v=\sqrt{\frac{T}{m/L}}

where

T is the tension

m is the mass

L is the length

In this case, the length of the string is quadrupled, so the new length is:

L' = 4L

Substituting into the equation, we find that the new speed is:

v'=\sqrt{\frac{T}{m/L'}}=\sqrt{\frac{T}{m/(4L)}}=\sqrt{4}\sqrt{\frac{T}{m/L}}=2v

So, the speed of the wave will  double.

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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4 years ago
The asteroid belt is a region between Mars and Jupiter that contains a multitude of large rocks and planetary fragments called a
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The best estimate of the orbital period of a typical asteroid is 9.0 earth years. 
7 0
3 years ago
A 0.717kg block is attached to a spring with spring constant 19.32N/m. While the block is sitting at rest, a student hits it wit
hjlf

Answer:

15.38 m.

Explanation:

The kinetic energy of the block is equal to potential energy of spring at maximum compression

1/ 2 m V² = 1 /2 K X²

m is mass of block , V is its velocity , K is spring constant and  X is maximum compression or its amplitude.

X = V\times\sqrt{\frac{m}{K} }

Putting the values

x = 79.856\times\sqrt{\frac{.717}{19.32} }

= 15.38 m.

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3 years ago
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