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4 years ago

9

While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th

e motion somewhat unpleasant. To take your mind off your stomach, you wonder about the motion of the ride. You estimate the radius of the big wheel to be 14 mm , and you use your watch to find that each loop around takes 23 ss .

1 answer:

Eduardwww [97]4 years ago

4 0

Answer:

$\omega = 0.273 rad/s$

$v = 3.825 m/s$

Explanation:

Assuming that the question is asking for the angular and linear speed of the Ferris wheel, we can solve by converting from period of 1 revolution (23 s) to angular speed knowing that 1 revolution would sweep and angle of 2π.

$\omega = \frac{2\pi}{T} = \frac{2\pi}{23} = 0.273 rad/s$

We can calculate the linear speed of the motion from the angular speed and the radius

$v = \omega r = 0.273 * 14 = 3.825 m/s$

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Anit [1.1K]

Answer:

20 gram of H as the greastest volume

Explanation:

Each gas sample has the same temperature and pressure. which sample occupies the greatest volume? each gas sample has the same temperature and pressure. which sample occupies the greatest volume? 40.0 gar 20.0 gne 20.0 gh2 4.0 ghe

Given that,

40.0 g of Ar

20.0 g of Ne

20.0 g of h

24.0 g of he

The ideal gas equation ; Pv = nRT

where P is the pressure, V is the volume, R is the gas constant, T is the temperature, n is the number of mole

which is equal to

n = m / M

where m is the given mass

M is the molar mass

The given gas sample are at the same temperature and pressure,

So, the temperature, pressure and gas constant are fixed.

Therefore the volume is proportional to the given mass and molar mass

V ∝ m/M

Substitute the given mass and molar mass of given masses for comparison

No of mole of Ar = mass / molar mass

= 40 / 40 = 1 mole

No of mole of Ne = mass / molar mass

= 20 / 20 = 1 mole

No of mole of h = mass / molar mass

= 20 / 1 = 20 mole

No of mole of he = mass / molar mass

= 24 / 4 = 6 mole

Hence, 20 gram of H as the greastest volume

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3 years ago

A single-turn circular loop of radius 14 cm is to produce a field at its center that will just cancel the earth's magnetic field

Olin [163]

Answer:

49 A

Explanation:

We are given that

Number of turns,N=1

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$1G=10^{-4} T$

$\mu_0=4\pi\times 10^{-7} Tm/A$

We know that magnetic field

$B=\frac{\mu_0IN}{2\pi r}$

Substitute the values

$0.7\times 10^{-4}=\frac{4\pi\times 10^{-7}\times 1\times I}{2\pi\times 0.14}$

$I=\frac{0.7\times 10^{-4}\times 2\pi\times 0.14}{4\pi\times 10^{-7}\times 1}$

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3 years ago

) Water flows through a horizontal coil heated from the outside by high-temperature flue gases. As it passes through the coil th

Mademuasel [1]

Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

$m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w$

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Putting the given values into the above formula as follows.

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q = 6597.711 kJ

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