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Stolb23 [73]
3 years ago
12

A single-turn circular loop of radius 14 cm is to produce a field at its center that will just cancel the earth's magnetic field

at the equator, which is 0.7 g directed north. the permeability of free space is 4 π × 10−7 t · m/a. find the current in the loop. answer in units of a
Physics
1 answer:
Olin [163]3 years ago
6 0

Answer:

49 A

Explanation:

We are given that

Number of turns,N=1

Radius,r=14 cm=\frac{14}{100}=0.14 m

1 m=100 cm

Magnetic field,B=0.7 G=0.7\times 10^{-4} T

1G=10^{-4} T

\mu_0=4\pi\times 10^{-7} Tm/A

We know that magnetic field

B=\frac{\mu_0IN}{2\pi r}

Substitute the values

0.7\times 10^{-4}=\frac{4\pi\times 10^{-7}\times 1\times I}{2\pi\times 0.14}

I=\frac{0.7\times 10^{-4}\times 2\pi\times 0.14}{4\pi\times 10^{-7}\times 1}

I=49A

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