Answer: Metals are malleable. Most metallic elements are solids at room temperature.
Explanation:
To solve the question you use the following formula:
concentration (1) × volume (1) = concentration (1) × volume (1)
3 M × volume (1) = 1.8 M × 50 mL
volume (1) = (1.8 M × 50 mL) / 3 M = 30 mL
Answer:
15 electrones: 1S²2S²2P⁶3S²3P³. Fósforo
27 electrones: 1S²2S²2P⁶3S²3P⁶4S²3d⁷ - Cobalto.
56 electrones: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s² - Bario
49 electrones: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p¹ - Indio
Explanation:
Para llenar los orbitales electrónicos de los distintos átomos debemos hacer uso de la regla de llenado electrónico de Aufbau. Por ejemplo, para el átomo con 15 electrones, la configuración electrónica es:
1S²2S²2P⁶3S²3P³. 2+2+6+2+3 = 15 electrones
Si elemento es neutro, tiene 15 protones. Es decir, es el fósforo, P.
27 electrones:
1S²2S²2P⁶3S²3P⁶4S²3d⁷ - Cobalto.
56 electrones:
1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s² - Bario
49 electrones:
1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p¹ - Indio
When using filter paper chromatography to separate ink, one will observe that more colours are mixed into darker inks. The darker an ink is, the more the colours that will be separated out during chromatography process. Thus, the observation that the darker the ink, the more colours are mixed into it will lead one to believe that ink is a mixture.
Answer:
4.375 milligram
Explanation:
Applying,
A = A'(2ᵃ/ⁿ)............. Equation 1
Where A = original amount of actinium-228, A' = amount of actinium-228 left after decay, a = Total time, n = half life
make A' the subject of the equation
A' = A/(2ᵃ/ⁿ)........... Equation 2
From the question,
Given: A = 70 milligram, a = 24.52 hours, n = 6.13 hours
Substitute these values into equation 2
A' = 70/(2²⁴°⁵²/⁶°¹³)
A' = 70/(2⁴)
A' = 70/16
A' = 4.375 milligram
