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olasank [31]
3 years ago
5

Help help help help

Chemistry
1 answer:
Lelu [443]3 years ago
6 0
Mean: 32.55
Median: 11
Mode: 0
Range: 0-116
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The substance oxidized causes the other substance to be reduced and is called the:.
blsea [12.9K]

Answer:hydrogen Peroxide

Explanation:

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Which element is best known for it's bad smell?
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The bad smelling element is Sulfur, which smells like rotting eggs.
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Which statement is true about AC?
AysviL [449]

According to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.

<h3>What is AC?</h3>

It is the flow of electric charges through a conductor is called electric current, if said flow of electric current varies in direction from time to time, we speak of alternating current.

Subatomic particles such as protons and electrons have an electrical charge, a physical property that is manifested by the repulsive and attractive forces that exist between them in AC the electrical charge moves back and forth.

Therefore, we can conclude that according to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.

Learn more about AC here: brainly.com/question/11695848

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3 0
1 year ago
What is the wavelength (in nm) of
LenKa [72]

Answer:

λ = 0.45×10⁻⁶ m

Explanation:

Given data:

Wavelength of blue light = ?

Frequency of blue light = 6.69×10¹⁴ s⁻¹

Solution:

Formula;

Speed of wave = wavelength × frequency

Speed of wave = 3.00×10⁸ m/s

by putting vales,

3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹

λ = 3.00×10⁸ m/s / 6.69×10¹⁴ s⁻¹

λ = 0.45×10⁻⁶ m

6 0
2 years ago
Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0
olya-2409 [2.1K]

Answer:

pH=-1.37

Explanation:

We are given that 25 mL of 0.10 M CH_3COOH is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of CH_3COOH=25mL=0.025 L

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL=\frac{35}{1000}=0.035 L

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of CH_3COOH=0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+=0.10\times 0.025=0.0025 moles

Number of moles of OH^-=0.10\times 0.01=0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+=\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L

pH=-log [H+]=-log [4.28\times 10^{-2}]=-log4.28+2 log 10=-0.631+2

pH=-1.37

6 0
3 years ago
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