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BlackZzzverrR [31]
2 years ago
14

The density of titanium is 4.51 g/cm^3. what is the volume (in cubic inches) of 3.5 lb of titanium?

Chemistry
2 answers:
Lina20 [59]2 years ago
4 0
<span>(3.5 lb Ti) x (453.592 g Ti / 1 lb Ti) x (1 cm^3 Ti / 4.51 g Ti) x 0.0610237 in^3 / 1 cm^3) = 21 in^3 Ti. Use factor label method to cancel out units and make sure to cancel out the units to the solution, which in this case is volume of titanium in cubic inches. We only keep two digits because the original numbers use have two sig figs as the least amount when doing multiplication or division.</span>
zepelin [54]2 years ago
4 0

The volume of 3.5 lb of titanium in cubic inches is  21.48 inch³

<h2>Further Explanation;</h2><h3>Density </h3>
  • Density refers to the measure of compactness of a material.
  • It is the mass of a substance or material per unit volume.
  • Mathematically;

Density = \frac{mass}{Volume}

  • Density is measured in g/cm³ or kg/m³
<h3>Mass </h3>
  • Mass refers to the amount of matter in a substance.
  • The S.i units of mass is Kg but can be measured using other units such as grams.
<h3>Volume </h3>
  • Volume refers to the space occupied by a substance or a shape.
  • The S.I. units of volume is m³, but can be measured using other units such as cm³, in³, etc.

  • From the question above;

Density = 4.51 g/cm^{3} \\Mass = 3.5 pounds

But;

1 pound = 453.592 grams

Therefore;

3.5 pounds = (3.5 × 453.592)

                  = 1,587.57 grams

But;

Volume = \frac{Mass}{Density}

Thus;

volume = \frac{1,587.57 g}{4.51 g/cm^{3} }

volume = 352.01 cm^{3}

But;

1 inch³ = 16.3871 cm³

Thus;

352.01 cm³ = (352.01 ÷ 16.3871 )inch³

                  =  21.48 inch³

The volume of 3.5 lb of titanium in cubic inches is  21.48 inch³

Keywords: Density, mass, volume

Learn more about:

  • Density; brainly.com/question/1398361
  • Mass: brainly.com/question/1398361
  • Volume; brainly.com/question/1398361

Level: High school

Subject: Physics

Topic: Mass, volume and Density

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<h3>The features of different states of Matter:</h3>

Matter is defined as anything that has weight and occupies space.

There are three states of matter that is in existence which include:

  • Solid: The particles of solid are closely packed together and vibrate around fixed axes. That is why they have a definite shape and volume.

  • Liquid: The particles of liquid, though attracted to each other,move freely over each other. That is why they have definite volume but not a definite shape.

Therefore, a liquid occupies the shape of its container.

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Therefore, a gas neither has a definite shape nor volume.

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Read 2 more answers
What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10
vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

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D) Calcium

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