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BlackZzzverrR [31]
3 years ago
14

The density of titanium is 4.51 g/cm^3. what is the volume (in cubic inches) of 3.5 lb of titanium?

Chemistry
2 answers:
Lina20 [59]3 years ago
4 0
<span>(3.5 lb Ti) x (453.592 g Ti / 1 lb Ti) x (1 cm^3 Ti / 4.51 g Ti) x 0.0610237 in^3 / 1 cm^3) = 21 in^3 Ti. Use factor label method to cancel out units and make sure to cancel out the units to the solution, which in this case is volume of titanium in cubic inches. We only keep two digits because the original numbers use have two sig figs as the least amount when doing multiplication or division.</span>
zepelin [54]3 years ago
4 0

The volume of 3.5 lb of titanium in cubic inches is  21.48 inch³

<h2>Further Explanation;</h2><h3>Density </h3>
  • Density refers to the measure of compactness of a material.
  • It is the mass of a substance or material per unit volume.
  • Mathematically;

Density = \frac{mass}{Volume}

  • Density is measured in g/cm³ or kg/m³
<h3>Mass </h3>
  • Mass refers to the amount of matter in a substance.
  • The S.i units of mass is Kg but can be measured using other units such as grams.
<h3>Volume </h3>
  • Volume refers to the space occupied by a substance or a shape.
  • The S.I. units of volume is m³, but can be measured using other units such as cm³, in³, etc.

  • From the question above;

Density = 4.51 g/cm^{3} \\Mass = 3.5 pounds

But;

1 pound = 453.592 grams

Therefore;

3.5 pounds = (3.5 × 453.592)

                  = 1,587.57 grams

But;

Volume = \frac{Mass}{Density}

Thus;

volume = \frac{1,587.57 g}{4.51 g/cm^{3} }

volume = 352.01 cm^{3}

But;

1 inch³ = 16.3871 cm³

Thus;

352.01 cm³ = (352.01 ÷ 16.3871 )inch³

                  =  21.48 inch³

The volume of 3.5 lb of titanium in cubic inches is  21.48 inch³

Keywords: Density, mass, volume

Learn more about:

  • Density; brainly.com/question/1398361
  • Mass: brainly.com/question/1398361
  • Volume; brainly.com/question/1398361

Level: High school

Subject: Physics

Topic: Mass, volume and Density

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swat32

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Next, we shall write the balanced equation for the reaction. This is given below:

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Finally, we determine the number of mole of PCl5 produced from the reaction as follow:

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