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____ [38]
3 years ago
13

A compound's properties are different than the properties of the elements that make it up.

Chemistry
1 answer:
yan [13]3 years ago
7 0
The answer is True because elements in a compound combine and become an entirely different substance with its own unique properties.
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Acid/base, precipitation, redox, or none:. 1. Ba(ClO3)2(s) ----> BaCl2(s) + 3O2(g). 2. CaO(s) +CO2(g) ----> CaCO3(s)
Aleks04 [339]
There are two equations given in the question. The type of reaction shown can be easily judged, if one takes a closer look at the equations.

1. <span>Ba(ClO3)2(s) ----> BaCl2(s) + 3O2(g) ------- Redox

2. </span><span>CaO(s) +CO2(g) ----> CaCO3(s) -------- None.

I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>
4 0
3 years ago
What is the mass of Na2CO3 required to make a
Paladinen [302]

Answer:

21.2 g

Explanation:

Step 1: Given data

  • Molar concentration of the solution (C): 0.400 mol/L
  • Volume of solution (V): 500 mL (0.500 L)

Step 2: Calculate the moles of Na₂CO₃ (solute) in the solution

We will use the definition of molarity.

C = moles of solute / liters of solution

moles of solute = C × liters of solution

moles of solute = 0.400 mol/L × 0.500 L = 0.200 mol

Step 3: Calculate the mass corresponding to 0.200 moles of Na₂CO₃

The molar mass of Na₂CO₃ is 105.99 g/mol.

0.200 mol × 105.99 g/mol = 21.2 g

8 0
3 years ago
Why is the Milky Way considered a galaxy
Lady_Fox [76]

Answer:

Explanation:

All the stars we see in the night sky are in our own Milky Way Galaxy. Our galaxy is called the Milky Way because it appears as a milky band of light in the sky when you see it in a really dark area.

3 0
3 years ago
Read 2 more answers
How many moles of chloride ions are there in 2 moles of calcium chloride?
Oksana_A [137]

Answer:

  • <em>There are </em><u><em>4 moles</em></u><em> of chloride ions in 2 moles of calcium chloride.</em>

Explanation:

Start by writing the chemical formula of calcium chloride.

The suffix -ide in chloride means that chlorine is working as the ion Cl⁻, this is with oxidation state -1.

Calcium, being an alkaline earth metal, uses oxidation state +2, Ca²⁺

Then, two atoms of Cl are combined with one atom of calcium, because in this way each Cl atom will accept one electron from a Ca atom, which will donate its two valence electrons.

That is indicated in the chemical formula with subscripts: <u><em>CaCl₂</em></u>, meaning that each formula-unit of calcium chloride has 2 ions of chlorine and 1 ions of calcium, or twice the number of moles of chloride ion.

  • 1 mol CaCl₂ : 1 mol Ca⁺ : 2 mol Cl⁻

       ⇒ 2 mol CaCl₂ : 2 mol Ca⁺ : 4 mol Cl⁻

Hence, there are 4 moles of chloride ions in 2 moles of calcium chloride.

6 0
3 years ago
A 21.8 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ris
Blababa [14]

<u>Answer:</u> The heat capacity of calorimeter is 15.66J/^oC

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethanol = 21.8 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

\text{Moles of ethanol}=\frac{21.8g}{46.07g/mol}=0.473mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.473 moles

\Delta H_{rxn} = enthalpy change of the reaction  = -1235 kJ/mol = -1235\times 10^3J/mol     (Conversion factor:  1 kJ = 1000 J)

Putting values in above equation, we get:

-1235\times 10^3J/mol=\frac{q}{0.473mol}\\\\q=(-1235\times 10^3J/mol\times 0.473mol)=-584.16\times 10^3J

To calculate the heat capacity of calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed by the calorimeter = 584.16\times 10^3J

c = heat capacity = ?

\Delta T = change in temperature = T_2-T_1=62.3^oC-25^oC=37.3^oC

Putting values in above equation, we get:

584.16\times 10^3J=c\times 37.3^oC\\\\c=\frac{584.16\times 10^3J}{37.3^oC}=15.66J/^oC

Hence, the heat capacity of calorimeter is 15.66J/^oC

4 0
4 years ago
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