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guapka [62]
4 years ago
14

Can I get some help please!!

Mathematics
1 answer:
Airida [17]4 years ago
5 0

Answer:

  a.  -3

  b.  -3

Step-by-step explanation:

Fill in the function arguments and simplify.

a.

\dfrac{f(x)-f(a)}{x-a}=\dfrac{(-3x+9)-(-3a+9)}{x-a}=\dfrac{-3x+9+3a-9}{x-a}\\\\=\dfrac{-3(x-a)}{(x-a)}=-3

__

b.

\dfrac{f(x+h)-f(x)}{h}=\dfrac{(-3(x+h)+9)-(-3x+9)}{h}=\dfrac{-3x-3h+9+3x-9}{h}\\\\=\dfrac{-3h}{h}=-3

_____

<em>Comment on questions of this type</em>

Perhaps the point of this exercise is to help you understand that the average slope computed by the first expression approaches the instantaneous slope computed by the second expression. This happens when a approaches x and when h approaches zero.

In this problem, where the function is a straight line, the slope is a constant (-3), so the average slope and the instantaneous slope are the same everywhere (for all values of x, a, h).

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UNO [17]
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Make your fractions have common denominators 
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Add your fractions and simplify
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or
13-(31/20)
or
13-(1 11/20)
Then turn 13 into a fraction with a common denominator! Im going to use the second fraction method (31/20)
13 written as a fraction is 13/1, its LCD with 31/20 is 20. I now multiply the top and bottom by 20
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6 0
4 years ago
Which of the following has a constant of proportionality of 2? A) y = 2x B) y = x + 2 C) 2y = x D) y + 2 = 2x
Setler [38]

The correct answer is A.


You have direct variation if x and y are modeled by the equation


y = mx


In this case, m is the constant of proportionality. So, if the constant has to be 2, the equation becomes


y = 2x


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5 0
4 years ago
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5 0
3 years ago
Which expression is equivalent to 5(w+4) when w=9
erica [24]

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Step-by-step explanation:

8 0
3 years ago
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In the parallelogram DEFG, DH=x+1, HF=3y, GH=3x-4, and HE=5y+1. Find the values of x and y. The diagram is not drawn to scale.
RideAnS [48]

Answer:

Step-by-step explanation:

Given:  In parallelogram DEFG,

DH = x + 1

HF = 3y

GH = 3x - 4

and HE = 5y + 1

Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore

x+1=3y            (1)

3x-4=5y+1      (2)

Multiply equation (1) with 3 and then subtract equation (2) from it, we get

3x+3-3x+4=9y-5y-1

7=4y-1

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Substituting the value of y=2 in equation (1), we get

x+1=3(2)

x=5

Therefore, the value of x and y are 5 and 2 respectively.

8 0
4 years ago
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