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makkiz [27]
3 years ago
11

Which item is an example of a primary source? A. An academic paper analyzing John F. Kennedy's presidency B. A transcript of a p

residential speech C. A textbook about American foreign policy D. A newspaper article reflecting on the anniversary of the end of the Cold War
Physics
1 answer:
Viktor [21]3 years ago
7 0

A transcript of a presidential speech (APEX Class ;)

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A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?
prohojiy [21]

Answer:

<h3>62.5N</h3>

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

A2 = 0.5m²

F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

125 = 2F2

F2 = 125/2

F2 = 62.5N

Hence the  force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N

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3 years ago
If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a result?
Fittoniya [83]

Answer:

The Kinetic Energy decreases. The Total Energy stays the same

Explanation:

The TE stays the same, so if PE increases then KE will decrease.

7 0
3 years ago
Free p o i n t s. hurry before admin deletes ;-;
blsea [12.9K]
The answer is 3+5+4 = 10+3 so then you have to add the number to the part of the equation and you will get the answer of five
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3 years ago
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Answer:

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Explanation:

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3 years ago
If the gas mileage of a Honda Civic car is 38 miles per gallon how many liters of gasoline would the car use to move from the Es
Troyanec [42]

Answer:

<em>6.25</em>

Explanation:

 M = d/g........................ Equation 1

making g the subject of the equation,

g = d/M............................. Equation 2

Where M = mileage per gallon, d = distance move from Essex campus to Catonsville campus,  g = amount of gasoline used

<em>Given: M = 38 miles per gallon, d = 37.2 km</em>

<em>If 1 kilometer =  0.62 miles</em>

<em>Then, 37.2 km = 37.2×0.62 miles = 23.064 miles</em>

<em>Substituting these values into equation 2,</em>

<em>g = 38/23.064</em>

<em>g = 1.648 gallon</em>

<em>g ≈1.65 gallon</em>

<em>Thus, </em>

<em>If,     0.264 gallon = 1 liters.</em>

<em>Then, 1.65 gallon = 1.65×1/0.264 = 6.25 liters.</em>

<em>g = 6.25</em>

<em>Thus the car will use 6.25 liters of gasoline to move from the Essex campus to the Catonsville campus.</em>

8 0
3 years ago
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